Two force are simultaneously applied on an object. What third force would make the net force to point to the left ($-x$ direction)

Three forces $F_1,F_2$ and $F_3$ act on an object simultaneously. These force vectors are shown in the following free body diagram. In which direction does the object accelerate?

The adjoining figure shows a force of $40 \mathrm{N}$ pulling a body of mass $5 \mathrm{kg}$ in a direction $30°$ above the horizontal. The body is in rest on a smooth horizontal surface. Assuming acceleration of free-fall is $10 \mathrm{m} {\mathrm{s}}^{-2}$. Which of the following statements I and II is/are correct?

I. The weight of the $5 \mathrm{kg}$ mass acts vertically downwards

II. The net vertical force acting on the body is $30 \mathrm{N}$.

A block of weight $W$ is suspended by a string of fixed length. The ends of the string are held at various positions as shown in the figures below. In which case, if any, is the magnitude of the tension along the string largest?

An ideal string is passing over a smooth pulley as shown. Two blocks $m_1$ and $m_2$ are connected at the ends of the string. If $m_1=1 \mathrm{kg}$ and tension in the string is $10 \mathrm{N}$, mass $m_2$ is equal to $\left(g=10 \mathrm{m} {\mathrm{s}}^{-2}\right)$

A point mass $m$ is suspended from a light thread of length $\mathcal{l},$ fixed at $O$, is whirled in a horizontal circle at constant speed as shown. From your point of view, stationary with respect to the mass, the forces on the mass are:

A small object, suspended by a string, rotates with constant speed, in a horizontal circle as shown in the figure. Point $O$ is at the centre of the circle. Neglect air drag. Which one of the following statement is correct?