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Two hydrogen atoms are in excited state with electrons residing in n=2. First one is moving towards left and emits a photon of energy E1 towards right. Second one is moving towards right with same speed and emits a photon of energy E2 towards right. Taking recoil of nucleus into account during emission process

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Important Questions on Modern Physics - I

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In a hydrogen atom following the Bohr's postulates the product of linear momentum and angular momentum is proportional to (n)x where 'n' is the orbit number. Then 'x' is:
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The wavelengths of Kαx-rays of two metals 'A' and 'B' are 41875R and 1675R respectively, where R is Rydberg's constant. The number of elements lying between 'A' and 'B' according to their atomic numbers is
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One of the lines in the emission spectrum of Li2+ has the same wavelength as that of the 2nd  line of Balmer series in hydrogen spectrum. The electronic transition corresponding to this line is:
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If the short wavelength limit of the continuous spectrum coming out of a Coolidge tube is 10 A°, then the de-Broglie wavelength of the electrons reaching the target metal in the Coolidge tube is approximately:
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The photon radiated from hydrogen corresponding to 2nd  line of Lyman series is absorbed by a hydrogen like atom 'X' in 2nd  excited state. As a result the hydrogen like atom 'X' makes a transition to nth  orbit. Then,
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In a photoelectric experiment, with light of wavelength λ, the fastest electron has speed v. If the exciting wavelength is changed to 3λ4, the speed of the fastest emitted electron will become
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The element which has a Kα X-rays line of wavelength 1.8 Å is R=1.1×107m-1, b=1 and 5/33=0.39

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When an electron accelerated by potential difference U is bombarded on a specific metal, the emitted X-ray spectrum obtained is shown in adjoining graph. If the potential difference is reduced to U3, the correct spectrum is

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