Two ideal batteries and two ammeters are arranged as shown in the figure.

Two ideal batteries and two ammeters are arranged as shown in the figure.

In the above figure, if the polarity of $E_2$ is reversed, then

In the figure, the voltmeter is not ideal. If the voltmeter is removed from $R_1$, and then put across $R_2$, what will be the effect on current $I$? Given $R_1>R_2$

Three ammeters $A, B$ and $C$ of resistances $R_A, R_B$ and $R_C,$ respectively, are joined as shown in the figure.

When some potential difference is applied across the terminals $T_1$ and $T_2,$ their readings are $I_A, I_B$ and $I_C,$ respectively, then

A battery of emf ${\mathrm{\epsilon }}_0=5 \mathrm{V}$ and internal resistance $5 \mathrm{\Omega }$ is connected across a long uniform wire $AB$ of length $1 \mathrm{m}$ and resistance per unit length $5 \mathrm{\Omega } {\mathrm{m}}^{-1}$. Two cells of ${\mathrm{\epsilon }}_1=1 \mathrm{V}$ and ${\mathrm{\epsilon }}_2=2 \mathrm{V}$are connected as shown in the figure.

A circuit is shown below: