MEDIUM
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Two moles of an ideal gas have undergone a cyclic process 1  2  3  1 . If net heat exchange in the process is -300 J , then work done by the gas in the process 2-3 is R=8.3 J mol-1 K-1

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Important Questions on Thermodynamics

HARD
An ideal gas undergoes a quasi-static, reversible process in which its molar heat capacity C remains constant. If during this process the relation of pressure P and volume V is given by PVn= constant, then n is given by (Here CP and CV are molar specific heat at constant pressure and constant volume, respectively) :
HARD

The equation of state of nmoles of a non-ideal gas can be approximated by the equation p+n2aV2(V-nb)=nRT where, a and, b are constant characteristics of the gas. Which of the following can represent the equation of a quasi-static adiabatic for this gas (assume that, CV is the molar heat capacity at constant volume is independent of temperature)?

MEDIUM

Two moles of an ideal monoatomic gas occupies a volume V at 27oC . The gas expands adiabatically to a volume 2V. Calculate (a) the final temperature of the gas and (b) change in its internal energy.

HARD
An ideal gas is undergoing a cyclic thermodynamic process in different ways as shown in the corresponding P-V diagrams in column 3 of the table. Consider only the path from state 1 to state 2. W denotes the corresponding work done on the system. The equations and plots in the table have standard notations as used in thermodynamic process. Here γ is the ratio of heat capacities at constant pressure and constant volume. The number of moles in the gas is n.
 
Column – 1 Column – 2 Column – 3
(I) W12=1γ-1P2V2-P1V1 (i) Isothermal (P) Question Image
(II) W12= -PV2+PV1 (ii) Isochoric (Q) Question Image
(III) W12=0 (iii) Isobaric (R) Question Image
(IV) W12= -nRTlnV2V1 (iv) Adiabatic (S) Question Image
Which of the following options is the only correct representation of the process U=Q-PV ?
HARD
A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure Pi=105 Pa and volume Vi=10-3 m3 changes to a final state at Pf=132×105 Pa and Vf=8×10-3 m3 in an adiabatic quasi-static process, such that P3V5= constant. Consider another thermodynamic process that brings the system from the same initial state to the same final state in two steps: an isobaric expansion at Pi followed by an isochoric (isovolumetric) process at volumes Vf . The amount of heat supplied to the system in the two step process is approximately
EASY
The ratio of work done by an ideal monoatomic gas to the heat supplied to it in an isobaric process is
EASY
One mole of a monoatomic ideal gas expanded by a process described by PV3=C where C is a constant. The heat capacity of the gas during the process is given by ( R is the gas constant)
HARD
A thermodynamic cycle xyzx is shown on a V - T diagram.
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The P - V diagram that best describes this cycle is: (Diagrams are schematic and not to scale)
HARD
One mole of an ideal monatomic gas is taken along the path ABCA as shown in the P-V diagram. The maximum temperature attained by the gas along the path BC is given by:
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MEDIUM
One mole of an ideal monatomic gas undergoes a process described by the equation PV3= constant. The heat capacity of the gas during this process is
EASY
A diatomic gas with rigid molecules does 10 J of work when expanded at constant pressure. What would be the heat energy absorbed by the gas, in this process?
HARD
A gas obeying the equation of state PV=RT undergoes a hypothetical reversible process described by the equation, PV53exp-PVE0=C1, where C1 and E0 are dimensioned constants. Then, for this process, the thermal compressibility at high temperature
EASY
n moles of an ideal gas with constant volume heat capacity Cv undergo an isobaric expansion by certain volume. The ratio of the work done in the process, to the heat supplied is:
MEDIUM
One mole of an ideal monatomic gas undergoes an adiabatic expansion in which its volume becomes eight times its initial value. If the initial temperature of the gas is 100K and the universal gas constant R=8.0 J mol-1 K-1, then how much is the decrease in its internal energy (in J) ?
MEDIUM
A sample of an ideal gas is taken through the cyclic process abca as shown in the figure. The change in the internal energy of the gas along the path ca is -180 J. The gas absorbs 250 J of heat along the path ab and 60 J along the path bc . The work done by the gas along the path abc is:
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MEDIUM
Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently, the mean collision time between the gas molecule changes from τ1 to τ2 . If CPCv=γ for this gas then a good estimate for τ2τ1 is given by
MEDIUM
Which of the following is an equivalent cyclic process corresponding to the thermodynamic cyclic given in the figure? Where, 12 is adiabatic. (Graphs are schematic and are not to scale)
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EASY
A gas at initial temperature T undergoes sudden expansion from volume V to 2V. Then.
EASY
Figure below shows two paths that may be taken by a gas to go from a state A to a state C.
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In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be:
MEDIUM
An ideal gas goes through a reversible cycle abcd has the V - T diagram shown below. Process da and bc are adiabatic.

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The corresponding P - V diagram for the process is (all figures are schematic and not drawn to scale) :