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Two parallel plate condensers of capacity of 20 μF and 30 μF are charged to the potentials of 30 V and 20 V, respectively. If likely charged plates are connected together, then the common potential difference will be

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Important Questions on Capacitance

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The work done in placing a charge of 8×10-18 coulomb on a condenser of capacity 100 micro-farad is
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A capacitor is charged by connecting a battery across its plates. It stores energy U. Now the battery is disconnected and another identical capacitor is connected across it, then the energy stored by both capacitors of the system will be
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In a parallel plate capacitor, the distance between the plates is d and potential difference across the plates is V. Energy stored per unit volume between the plates of the capacitor is
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A capacitor of capacitance C1 is charged upto potential V and then connected in parallel to an uncharged capacitor of capacitance C2. The final potential difference across each capacitor will be
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A parallel plate air capacitor is charged to a potential difference of V volts. After disconnecting the charging battery, the distance between the plates of the capacitor is increased using an insulating handle. As a result, the potential difference between the plates, 
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Two condensers, one of capacity C and the other of capacity C2 are connected to a V volt battery as shown. The work done in charging both the condensers fully is,

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The energy required to charge a parallel plate condenser of plate separation $d$ and plate area of cross-section $A$ such that the uniform electric field between the plates is $E$, is 

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A 40 μF capacitor in a defibrillator is charged to 3000 V. The energy stored in the capacitor is sent through the patient during a pulse of duration 2 ms. The power delivered to the patient is