Two particles approach each other with different velocities. After collision, one of the particles has a momentum $\overrightarrow{p}$ in their center of mass frame. In the same frame, the momentum of the other particle is

A particle of mass $m$ is moving along the $x‐$axis with speed $v$ when it collides with a particle of mass $2m$ initially at rest. After the collision, the first particle has come to rest, and the second particle has split into two equal-mass pieces that are shown in the figure. Which of the following statements correctly describes the speeds of the two pieces? $(\mathrm{\theta }> 0)$ 

Two blocks of masses $m$ and $M$ are moving with speeds $v_1$ and $v_2$ $({\mathrm{v}}_1>{\mathrm{v}}_2)$ in the same direction on the frictionless surface respectively, $M$ being ahead of $m$. An ideal spring of force constant $k$ is attached to the backside of $M$ (as shown). The maximum compression of the spring when the block collides is

Two masses are connected by a spring as shown in the figure. One of the masses was given velocity $v=2k$, as shown in figure where $k$ is the spring constant. Then maximum extension in the spring will be (initially spring is in natural length)

Mass $A$ hits $B$ inelastically $\left(e=0\right)$ while moving horizontally with some velocity along the common line of centres of the three equal masses each of same mass. Initially mass $B$ and $C$ are stationary and the spring is unstretched. Then which is incorrect.

A bullet of mass $m$ moving vertically upwards instantaneously with a velocity $u$ hits the hanging block of mass $m$ and gets embedded in it as shown in the figure. The height through which the block rises after the collision (assume sufficient space above block) is: