Two pipes A and B can fill a tank in $24$ minutes and $36$ minutes respectively.  In another pipe C can empty the filled tank in $18$ minutes. All three pipes A, B, and C are alternately open for $1$ minute each in the empty tank, such that pipe A is open first then pipe B, and then pipe C. At what time (in minutes), the tank will be filled?

Pipe A in comparison to pipe B fills a tank in one fourth time. Pipe C in comparison to pipe A takes 3 times more time to fill the tank. If the three pipes are opened together, the tank is filled in 24 hours. If Pipe C is not opened, how much time will it take to fill the tank?

Of the three pipes, the first two can fill an empty tank in 10.8 and 21.6 hours respectively, while the third pipe can empty the tank in 18 hours. If the tank is empty and all the three pipes are opened together then in how many hours will tank fill?

Two pipes separately take $5$ hours and $8$ hours respectively to fill a tank. The third pipe takes $3.2$ hours to drain out the water from the tank. How much time will all the three pipes take to fill the completely empty tank?

Quantity $1$: A pipe alone can fill a cistern in $60$ minutes. But due to leakage pipe filled only $80\%$ of the cistern in $60$ minutes. $"X"$ is the capacity of the cistern in litres and due to leakage $60$ litres were leaked out in $1$ hour.

Quantity $2$: $250$ litres.