Two players A and B plays a chess match. It is given that probability of winning the match by A is 5 6 . Find the probability of winning the match by B .

Given that, Probability of A winning the match, P ( A ) = 5 6 Now, probability of B winning the match, P ( B ) = probability of A losing the match = 1 - P ( A ) = 1 - 5 6 = 1 6 Hence, the probability of B winning the match is 1 6 .

Two players A and B plays a chess match. It is given that probability of winning the match by A is 5 6 . Find the probability of winning the match by B .

Given that, Probability of A winning the match, P ( A ) = 5 6 Now, probability of B winning the match, P ( B ) = probability of A losing the match = 1 - P ( A ) = 1 - 5 6 = 1 6 Hence, the probability of B winning the match is 1 6 .

In a bag one white ball, two black balls and three red balls of same size are placed. A ball is drawn at random from this bag. Find the probability : ball is not black.

Given: In a bag one white ball, two black balls and three red balls of same size are placed. A ball is drawn at random from this bag. Total number of possible outcomes = 1 + 2 + 3 = 6 Number of balls which are not black = 1 + 3 = 4 We know that, P ( A ) = Number of favourable outcomes Total number of outcomes Let A be event of not getting a black ball P A = 4 6 = 2 3 Hence, the probability of not getting a black ball is 2 3 .