How do you determine the resolving power of your eye?

We may perform a simple experiment to determine the resolving power of eye. We will make a pattern of black stripes of equal width separated by white stripes as shown in the figure below. All the black stripes should be of equal width, while the width of white stripes should increase from left to right. We have to paste the pattern at the height of our eye. By moving away or closer to the wall, we will find the position where we can see some two black stripes as separate stripes. ALL the black stripes which are left to it would merge into one another and on the right they would be more clearly visible. Note the width of the white stripe d that separates the two regions and measure the distance D of the eye from the wall. Then d D is the resolving power of our eye.

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Two points, separated by a distance of 0.1 mm, can just be inspected on a microscope when light of wavelength 6000 $Å$ is used. If the light of wavelength $4800 Å$ is used, the limit of resolution is

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Important Questions on Wave Optics

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Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 10 - Wave Optics>Exercise>Q 2

Wavelength of light used in an optical instrument are

λ_{1} = 4000 Å

and

λ_{2} = 5000 Å

,then ratio of their respective resolving powers ( corresponding to

λ_{1}

and

λ_{2}

) is

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Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 10 - Wave Optics>Exercise>Q 3

Resolving power of electron microscope varies with wavelength of electron. It can resolve a minimum distance upto

λ = 7.5 \times 10^{- 12} m

. Then minimum

K E

of electron it is used as electron microscope.

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Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 10 - Wave Optics>Exercise>Q 4

With the help of a telescope that has an objective of diameter 200 cm, it is proved that light of wavelengths of the order of 6400

Å

coming from a star be easily resolved. Then the limit of resolution is

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Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 10 - Wave Optics>Exercise>Q 5

Resolving power of a telescope will be more, if the diameter

(a)

of the objective is

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Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 10 - Wave Optics>Exercise>Q 6

Two stars are 10 light years away from the earth. They are seen through a telescope of objective diameter 30 cm. The wavelength of light is 600nm. To see the stars just resolved by the telescope, the minimum distance between them should be

(1 l i g h t y e a r = 9.46 \times 10^{15} m)

of the order of :

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Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 10 - Wave Optics>Exercise>Q 7

Phase contrast microscope was invented by:

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Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 10 - Wave Optics>Exercise>Q 8

Assuming human pupil to have a radius of

0.25 cm

and a comfortable viewing distance of

25 cm

, the minimum separation between two objects that human eye can resolve at

500 nm

wavelength is

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Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 10 - Wave Optics>Exercise>Q 9

The semi vertical angle of cone of the rays incident on the objective of microscope is

20 ° .

If the wavelength of incident light ray is

6600

\overset{°}{A}

. Calculate the smallest distance between two points which can be just resolved.

Two points, separated by a distance of 0.1 mm, can just be inspected on a microscope when light of wavelength 6000 Å is used. If the light of wavelength 4800Å is used, the limit of resolution is

Important Questions on Wave Optics

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Two points, separated by a distance of 0.1 mm, can just be inspected on a microscope when light of wavelength 6000 $Å$ is used. If the light of wavelength $4800 Å$ is used, the limit of resolution is