HARD
JEE Main
IMPORTANT
Earn 100

Two substances R and S decompose in a solution independently, both following first order kinetics. The rate constant of R is twice that of S. In an experiment, the solution initially contained 0.5 millimoles of R and 0.25 millimoles of S. The molarities of R and S will be equal just at the end of time equal to:

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Important Questions on Chemical Kinetics

HARD
JEE Main
IMPORTANT

Consider the reaction: Cl2(aq)+H2S(aq)S(s)+2H+(aq)+2Cl-(aq)

The rate equation for this reaction is:

Rate=KCl2H2S

Which of these mechanisms is/are consistent with this rate equation?

(A) Cl2+H2SH++Cl-+Cl++HS-(slow)        Cl++HS-H++Cl-+S (fast)

(B) H2SH++HS-(fast equilibrium      Cl2+HS-2Cl-+H++S (slow) 

 

HARD
JEE Main
IMPORTANT

For a second-order reaction of the type: a2Aa-xproducts,x/2

the rate law is given by:

rate  =- 12 d(a-x)dt =+d(x/2)dt = k2 (a-x)2

The Integrated rate law will be:

 

HARD
JEE Main
IMPORTANT

From the following data for the reaction between A and B :

 A, mol L-1  B, mol L-1  Initial rate, mol L-1 s-1, at 
     300 K  320 K
 2.5×10-4  3.0×10-5  5.0×10-4  2.0×10-3
 5.0×10-4  6.0×10-5  4.0×10-3  -
 1.0×10-3  6.0×10-5  1.6×10-2  -

If the pre-exponential factor is a×1017, find the value of 'a' up to the nearest integer.

HARD
JEE Main
IMPORTANT
The half-life of a substance in a first-order reaction is 100 minutes at 323.2 K and 15 minutes at 353.2 K. Calculate the temperature coefficient of the rate constant of this reaction.
HARD
JEE Main
IMPORTANT

The decomposition of PH3 at 950 K according to 4PH3(g)P4(g)+6H2(g) is a first-order reaction. The following measurements were made on a system containing only PH3 initially.

Time (min): 0 40 80
p (total mmHg): 100 150 166.7

Calculate the rate constant in min-1 .

HARD
JEE Main
IMPORTANT
A certain physiologically important first-order reaction has activation energy equal to 45.0 kJ mol-1at a normal body temperature 37 °C. Without a catalyst, the rate constant for the reaction is 5·0×10-4s-1. To be effective in the human body, where the reaction is catalysed by an enzyme, the rate constant must be at least 2·0×10-2s-1. If the activation energy is the only factor affected by the presence of the enzyme, by how much must the enzyme lower the activation energy of the reaction to achieve the desired rate?
HARD
JEE Main
IMPORTANT
A certain physiologically important first-order reaction has activation energy equal to 45.0 kJ mol-1 at normal body temperature 37 °C.Without a catalyst, the rate constant for the reaction is 5.0×10-4s-1. To be effective in the human body, where the reaction is catalysed by an enzyme, the rate constant must be at least 2·0×10-2s-1. If the activation energy is the only factor affected by the presence of the enzyme, by how much must the enzyme lower the activation energy of the reaction to achieve the desired rate?