EASY
12th ICSE
IMPORTANT
Earn 100

Two thin lenses of focal lengths 15 cm and 30 cm are placed in contact. What is the power of the system?

Important Questions on Refraction of Light at Spherical Surfaces : Lenses

EASY
12th ICSE
IMPORTANT

A thin convex lens of focal length 20 cm is kept in coaxial contact with another thin lens so that the combination becomes a converging lens of focal length 100 cm. What is the focal length of the second lens?

EASY
12th ICSE
IMPORTANT

A convex lens of focal length 30 cm is placed in contact with a concave lens of focal length 20 cm. Find the focal length and power of the combination. Is the combination converging or diverging?

MEDIUM
12th ICSE
IMPORTANT

Lenses of powers +3 D and -5 D are combined to form a compound lens. An object is placed at a distance of 50 cm from this lens. Calculate the position of its image.

MEDIUM
12th ICSE
IMPORTANT

A combination consisting of a concave lens in contact of a convex lens of focal length 25 cm produces a real image at a distance of 80 cm when an object is placed at a distance of 40 cm from the combination. Find the focal length and power of the concave lens.

MEDIUM
12th ICSE
IMPORTANT

Find the focal length and power of a convex lens which, when put in contact with a concave lens of focal length 25 cm forms a real image 5 times the size of an object placed 20 cm from the combination.

MEDIUM
12th ICSE
IMPORTANT

A compound lens is formed with two lenses of powers +15.5 D and -5.5 D kept in contact. A 3 cm long object is placed at a distance of 30 cm from the lens. What is the length of the image?

HARD
12th ICSE
IMPORTANT

Parallel rays of sun fall upon a concave lens of 10 cm focal length. At a distance of 20 cm from this lens, a convex lens of 15 cm focal length is placed. Where should the screen be placed to get the image of the sun?

HARD
12th ICSE
IMPORTANT

A point-object is situated at the centre of a solid glass sphere of radius 6 cm and refractive index 1.5. The distance of its virtual image from the surface of the sphere is: