At 700 K , CO 2 and H 2 react to form CO and H 2 O . For this purpose K c is 0 . 11 . If a mixture of 0 . 45 mole of CO 2 and 0 . 45 mole of H 2 is heated to 700 K , find out the amount of each gas at equilibrium.

Initial moles of CO 2 and H 2 = 0 . 45 , K c = 0 . 11 . Let, the degree of dissociation be x . CO 2 ( g ) + H 2 ( g ) ⇌ CO ( g ) + H 2 O ( g ) Initial moles: 0 . 45 0 . 45 0 0 Moles at equilibrium: 0 . 45 − x 0 . 45 − x x x K c = [ CO ] [ H 2 O ] [ CO 2 ] [ H 2 ] = x × x 0 . 45 − x 0 . 45 − x = 0 . 11 ⇒ x 0 . 45 − x = 0 . 33 ⇒ 1 . 33 x = 0 . 1485 ⇒ x = 0 . 11 . At equilibrium: [ CO 2 ] = [ H 2 ] = 0 . 45 - x = 0 . 45 - 0 . 11 = 0 . 34 mole [ CO ] = [ H 2 O ] = x = 0 . 11 mole .

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Vapour density of the equilibrium mixture of ${NO}_{2}$ and $N_{2} O_{4}$ is found to be $38.33$ : For the equilibrium $N_{2} O_{4} (g) ⇌ 2 {NO}_{2} (g)$ .

Calculate the abnormal molecular weight.

Important Questions on Chemical Equilibrium

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IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 6 - Chemical Equilibrium>DPP 6.4>Q 5

Vapour density of the equilibrium mixture of ${NO}_{2}$ and $N_{2} O_{4}$ is found to be $38.33$ : for the equilibrium $N_{2} O_{4} (g) ⇌ 2 {NO}_{2} (g)$ .

Calculate: degree of dissociation.

HARD

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 6 - Chemical Equilibrium>DPP 6.4>Q 5

Vapour density of the equilibrium mixture of ${NO}_{2}$ and $N_{2} O_{4}$ is found to be $38.33$ , for the equilibrium $N_{2} O_{4} (g) ⇌ 2 {NO}_{2} (g)$ .

Calculate the percentage of ${NO}_{2}$ in the mixture.

HARD

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 6 - Chemical Equilibrium>DPP 6.4>Q 5

Vapour density of the equilibrium mixture of ${NO}_{2}$ and $N_{2} O_{4}$ is found to be $38.33$ : for the equilibrium $N_{2} O_{4} (g) ⇌ 2 {NO}_{2} (g) .$

Calculate $K_{P}$ for the reaction if total pressure is $2 atm$ .

MEDIUM

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 6 - Chemical Equilibrium>DPP 6.4>Q 6

700 K, {CO}_{2}

and

H_{2}

react to form

CO

and

H_{2} O

. For this purpose

K_{c}

0.11 .

If a mixture of

0.45 mole

{CO}_{2}

and

0.45 mole

H_{2}

is heated to

700 K

, find out the amount of each gas at equilibrium.

HARD

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 6 - Chemical Equilibrium>DPP 6.4>Q 6

700 K, {CO}_{2}

and

H_{2}

react to form

CO

and

H_{2} O

. For this purpose

K_{c}

0.11 .

If a mixture of

0.45 mole

{CO}_{2}

and

0.45 mole

H_{2}

is heated to

700 K

when equilibrium has been reached, another

0.34 mole

{CO}_{2}

and

0.34 mole

H_{2}

are added to the reaction mixture. Find the composition of mixture at new equilibrium.

MEDIUM

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 6 - Chemical Equilibrium>DPP 6.4>Q 7

Two gases $A_{2}$ and $B_{2}$ are present in two containers at $300 K$ separated by a narrow tube of negligible volume having valve in between.

On opening the valve, the reaction $A_{2} (g) + B_{2} (g) \to 2 AB (g)$ attains equilibrium at $300 K$ . If $K_{C} = 4$ , at $300 K$ the concentration of $AB$ at equilibrium is:

Question Image

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IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 6 - Chemical Equilibrium>DPP 6.4>Q 8

10 %

of a mixture of

0.2 mole

N_{2}

and

0.6 mole

H_{2}

react to give

{NH}_{3}

according to the following reaction equilibrium:

N_{2} (g) + 3 H_{2} (g) ⇌ 2 {NH}_{3} (g)

at constant temperature. The ratio between the initial moles and final moles is

HARD

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part 1 JEE Main & Advanced>Chapter 6 - Chemical Equilibrium>DPP 6.4>Q 9

According to which of the following In the question,

α

varies with

\frac{D}{d}

Vapour density of the equilibrium mixture of NO2 and N2O4 is found to be 38.33: For the equilibrium N2O4(g)⇌2NO2(g). Calculate the abnormal molecular weight.

Important Questions on Chemical Equilibrium

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Vapour density of the equilibrium mixture of ${NO}_{2}$ and $N_{2} O_{4}$ is found to be $38.33$ : For the equilibrium $N_{2} O_{4} (g) ⇌ 2 {NO}_{2} (g)$ .

Calculate the abnormal molecular weight.