What can you say about $\cot 0°=\frac{1}{\tan 0°}?$ Is it defined ? Why?

Evaluate $\sin 45°+\cos 45°$

If $\frac{\cos 45°}{\sec 30°+cosec 60°}=\frac{\sqrt{3}}{k\sqrt{2}}$, then find the value of $k$

Evaluate the following.

$\frac{\sin 30°+\tan 45°-cosec 60°}{\cot 45°+\cos 60°-\sec 30°}$

Evaluate the following.

$2{\tan }^{2}45°+{\cos }^{2}30°-{\sin }^{2}60°$

Evaluate the following.

$\frac{{\sec }^{2}60°-{\tan }^{2}60°}{{\sin }^{2}30°+{\cos }^{2}30°}$

$\frac{2\tan 30°}{1+{\tan }^{2}45°}=$

$\frac{1-{\tan }^{2}45°}{1+{\tan }^{2}45°}=$