What do you mean by abscissa?

Match the following.

Draw the co-ordinate system on a plane and plot the following points.

$\mathrm{L}(-2,4), \mathrm{M}(5,6), \mathrm{N}(-3,-4), \mathrm{P}(2,-3), \mathrm{Q}(6,-5), \mathrm{S}(7,0), \mathrm{T}(0,-5)$

In the given figure, $PQRS$ is a rhombus whose diagonal $PR$ and $QS$ are along coordinate axis and $PR=12$ units and $QS=6$ units. Now, if$T$ is a point which is $5$ spaces right and $2$ spaces above $S$. Find
(i) Sum of abscissae of $P$ and $T$
(ii) sum of ordinates of $Q,R$ and $T$

The difference between ordinates of $R$ and $Q$ is

Some points are shown in the figure:

With the help of it answer the following question:

Which are the points whose $x$ and $y$ co-ordinates are equal?

Plot the point $\left(x,y\right)$ given in the following table on the plane, choosing suitable units of distance on the axis.

On a graph paper plot the points $\mathrm{A}\left(3,0\right)$, $\mathrm{B}\left(3,3\right)$, $\mathrm{C}\left(0,3\right)$. Join $\mathrm{A},\mathrm{B}$and $\mathrm{B},\mathrm{C}$. What is the figure formed?

Without plotting the points on a graph, state in which quadrant or on which axis do $\left(-6, 0\right)$ lie.

On a graph paper, plot the points $\mathrm{A}\left(2,3\right)$, $\mathrm{B}\left(6,-1\right)$ and $\mathrm{C}\left(0,5\right)$. If those points are collinear then draw the line which includes them. Write the co-ordinates of the points at which the line intersects the $\mathrm{X}-\mathrm{axis}$ and the $\mathrm{Y}-\mathrm{axis}$.

See the given figure, and find the coordinates of $\mathrm{B}.$