Obtain an expression for magnetic moment of an orbital electron.

Let us suppose, an electron revolving around a nucleus in an atom. As we know that, the electron is a negatively charged particle, so atom will act as a current carrying loop and the magnetic dipole moment of an electron is given by- M = I A Here, I is current and A is the area of the cross section. I = e t M = e t ( πr 2 ) where, I= current e=electron t=time ∵ t = 2 πr v Now, by putting the value of time t, we get, magnetic moment, M = e 2 πr × πr 2 v M = evr 2

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Physics Standard 12>Chapter 11 - Magnetic Materials>Use your brain power>Q 1

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What does the area inside the curve B - H (hysteresis curve) indicate?

Important Questions on Magnetic Materials

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Physics Standard 12>Chapter 11 - Magnetic Materials>Exercises>Q 1

Intensity of magnetic field of the earth at the point inside a hollow iron box is.

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Physics Standard 12>Chapter 11 - Magnetic Materials>Exercises>Q 1

Soft iron is used to make the core of transformer because of its

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Physics Standard 12>Chapter 11 - Magnetic Materials>Exercises>Q 1

Which of the following statements is correct for diamagnetic materials:

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Physics Standard 12>Chapter 11 - Magnetic Materials>Exercises>Q 1

A rectangular magnet suspended freely has a period of oscillation equal to T. Now it is broken into two equal halves ( each having half of the original length) and one piece is made to oscillate freely. Its period of oscillation is T', the ratio of T' / T is.

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Physics Standard 12>Chapter 11 - Magnetic Materials>Exercises>Q 1

A magnetising field of