EASY
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What is formula for end correction?

Important Questions on Superposition of Waves

EASY
Tube A has both ends open while tube B has one end closed. Otherwise, they are identical. The ratio of fundamental frequency of tube A and B is,
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A closed organ pipe has a fundamental frequency of 1.5 kHz. The number of overtones that can be distinctly heard by a person with this organ pipe will be (Assume that the highest frequency a person can hear is 20,000 Hz).
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A stationary tuning fork is in resonance with an air column in a pipe. If the tuning fork is moved with a speed of 2 m s-1 in front of the open end of the pipe and parallel to it, the length of the pipe should be changed for the resonance to occur with the moving tuning fork. If the speed of sound in air is 320 m s-1, the smallest value of the percentage change required in the length of the pipe is ________.
MEDIUM
A pipe open at one end has length 0.8 m. At the open end of the tube a string 0.5 m long is vibrating in its 1st overtone and resonates with fundamental frequency of pipe. If tension in the string is 50 N, the mass of string is (speed of sound =320 m s-1)
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The two nearest harmonics of a tube closed at one end and open at other end are 220 Hz and 260 Hz. What is the fundamental frequency of the system?
MEDIUM
On closing an open organ pipe from one end, it is noticed that the frequency of third harmonic is 50 Hz more than the fundamental frequency of vibration in open organ pipe. The fundamental frequency of open organ pipe is
MEDIUM

Show that only odd harmonics are present as overtones in the case of an air column vibrating in a pipe closed at one end.

HARD
Show that even as well as odd harmonics are present as overtones in the case of an air column vibrating in a pipe open at both the ends.
HARD
A pipe of length 85 cm is closed from one end. Find the number of possible natural oscillations of air column in the pipe whose frequencies lie below 1250 Hz. The velocity of sound in air is 340 m/s.
MEDIUM
A pipe open at both ends has a fundamental frequency f in air. The pipe is dipped vertically in water so that half of it is in water. The fundamental frequency of the air column is now:
EASY
A closed organ pipe and an open organ pipe have their first overtones identical in frequency. Their lengths are in the ratio
MEDIUM
The second overtone of an open organ pipe has the same frequency as the first overtone of a closed pipe which is  L meter long. The length of the open pipe will be
MEDIUM
A cylindrical tube open at both ends has a fundamental frequency f in air. The tube is dipped vertically in water so that 60 % of the tube is in water. Then the fundamental frequency of air column is
MEDIUM
If sound travels in air with the speed of 340 m s-1, then the number of tones present in an open organ pipe of length 2 m for a maximum frequency of 1200 Hz, are
EASY
First overtone frequency of a closed organ pipe of length L1 is equal to the 2nd  harmonic frequency of an open organ pipe of length L2. Then the ratio L1L2=?
EASY
The fundamental frequency in an open organ pipe is equal to the third harmonic of closed organ pipe. If the length of the closed organ pipe is 20 cm, the length of the open organ pipe is
HARD
Show that all harmonics are present in case of an air column vibrating in a pipe open at both ends.
MEDIUM
The number of possible natural oscillations of air column in a pipe closed at one end of length 85 cm whose frequencies lies below 1250 Hz are: (velocity of sound =340 ms-1)
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The fundamental frequency of an air column in a pipe closed at one end is 100 Hz. If the same pipe is open at both the ends, the frequencies produced in Hz are
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The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second overtone of an organ pipe open at both the ends. The length of the organ pipe open at both the ends is