What is the multiplicative inverse of $7$?

Mark the correct alternative in the following.

${\left(8^4+8^2\right)}^{\frac{1}{2}}=$

Mark the correct alternative in the following.

${\left(1+3+5+7+9+11\right)}^{\frac{3}{2}}=$

Evaluate:

$\left\{{\left(\frac{1}{3}\right)}^{-3}-{\left(\frac{1}{2}\right)}^{-3}\right\}÷{\left(\frac{1}{4}\right)}^{-3}$ 

Find the value of:

$\left(2^0+3^{-1}\right)\times 3^2$

Evaluate:

${\left\{{\left(\frac{-2}{3}\right)}^2\right\}}^{-2}$

Evaluate:

${\left\{{\left(\frac{4}{3}\right)}^{-1}-{\left(\frac{1}{4}\right)}^{-1}\right\}}^{-1}$ 

${\left\{{\left(33\right)}^2-{\left(31\right)}^2\right\}}^{\frac{5}{7}}=$

Mark the correct alternative in the following.

${\left(2^3\right)}^4=$

Fill in the blank with $>, <$ or $=$.

${\left(\frac{1}{2}\right)}^0$_____${\left(\frac{7}{4}\right)}^0$