Given below are the half - cell reactions : Mn 2 + + 2 e - → Mn ; E ∘ = - 1.18 V 2 Mn 3 + + e - → Mn 2 + ; E ∘ = + 1.51 V The E ∘ for 3 Mn 2 + → Mn + 2 Mn 3 + will be :

- 2.69 V ; the reaction will not occur

- 2.69 V ; the reaction will occur

- 0.33 V ; the reaction will not occur

- 0.33 V ; the reaction will occur

EASY

JEE Main

IMPORTANT

Earn 100

What is the standard reduction potential $(E^{o})$ for ${Fe}^{3 +} \to Fe ?$

Given that:

${Fe}^{2 +} + 2 e^{-} \to Fe; E_{{Fe}^{2 +} / Fe}^{o} = - 0 .47 V$

${Fe}^{3 +} + e^{-} \to {Fe}^{2 +}; E_{{Fe}^{3 +} / {Fe}^{2 +}}^{o} = + 0 .77 V$

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Important Questions on Electrochemistry

HARD

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 9 - Electrochemistry>JEE Main - 7th January 2020 Shift 2>Q 22

The equation that is incorrect is:

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 9 - Electrochemistry>JEE Main - 7th January 2020 Shift 1>Q 23

Given that the standard potentials

(E^{o})

{Cu}^{2 +} / Cu

and

{Cu}^{+} / Cu

are

0.34 V

and

0.522 V

respectively, the

E^{o}

{Cu}^{2 +} / {Cu}^{+}

is:

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 9 - Electrochemistry>JEE Main - 7th April 2013>Q 24

Four successive members of the first row of transition elements are listed below with atomic numbers. Which one of them is expected to have the highest

E_{M^{3 +} / M^{2 +}}^{o}

value?

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 9 - Electrochemistry>JEE Main - 7th April 2013>Q 25

Given

E_{{Cr}^{3 +} / Cr}^{o} = - 0.74 {V;  E}_{{MnO}_{4}^{-} / {Mn}^{2 +}}^{o} = 1.51 V

E_{{Cr}_{2} O_{7}^{2 -} / {Cr}^{3 +}}^{o} = 1.33 {V;   E}_{{Cl}_{2} | {Cl}^{-}}^{o} = 1.36 V

Based on the data given above, strongest oxidising agent will be:

HARD

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 9 - Electrochemistry>JEE Main - 6th April 2014>Q 26

Resistance of 0.2 M solution of an electrolyte is

50 Ω

. The specific conductance of the solution is

{1.4 S m}^{-1}

. The resistance of 0.5 M solution of the same electrolyte is

280 Ω

. The molar conductivity of 0.5 M solution of the electrolyte in

{S m}^{2} {mol}^{-1}

is :

HARD

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 9 - Electrochemistry>JEE Main - 6th April 2014>Q 27

The equivalent conductance of

NaCl

at concentration C and at infinite dilution are

λ_{C}

and

λ_{\infty}

, respectively. The correct relationship between

λ_{C}

and

λ_{\infty}

is given as :
(where the constant B is positive)

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 9 - Electrochemistry>JEE Main - 6th April 2014>Q 28

The metal that cannot be obtained by the electrolysis of an aqueous solution of its salt is

HARD

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 9 - Electrochemistry>JEE Main - 6th April 2014>Q 29

Given below are the half - cell reactions :

\begin{matrix} {Mn}^{2 +} + 2 e^{-} \to Mn; & E^{\circ} = - 1.18 V \\ 2 ({Mn}^{3 +} + e^{-} \to {Mn}^{2 +}); & E^{\circ} = + 1.51 V \end{matrix}

The

E^{\circ}

for

3 {Mn}^{2 +} \to Mn + 2 {Mn}^{3 +}

will be :

What is the standard reduction potential Eo for Fe3+→Fe? Given that: Fe2++2e-→Fe;EFe2+/Feo=-0.47V Fe3++e-→Fe2+;EFe3+/Fe2+o=+0.77V

Important Questions on Electrochemistry

Learn and Prepare for any exam you want !

What is the standard reduction potential $(E^{o})$ for ${Fe}^{3 +} \to Fe ?$

Given that:

${Fe}^{2 +} + 2 e^{-} \to Fe; E_{{Fe}^{2 +} / Fe}^{o} = - 0 .47 V$

${Fe}^{3 +} + e^{-} \to {Fe}^{2 +}; E_{{Fe}^{3 +} / {Fe}^{2 +}}^{o} = + 0 .77 V$