Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 30

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What will be the $KE$ of photoelectrons ejected, when a photon of $13 eV$ is absorbed by $H -$ atom in the third excited state.

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Important Questions on Structure of Atom

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 31

What is the ratio of the wavelengths of last lines of the Balmer and Lyman series for any hydrogen-like species?

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 32

An atom has

n

energy level, then the total number of lines in its spectrum are

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 33

A certain electronic transition from an excited state to the ground state in a sample of

H -

atoms gives rise to maximum of three lines in the ultraviolet region of the spectrum. How many lines does this transition produce in the infrared region of the spectrum?

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 34

What minimum number of atoms/ions should be present in a sample of

H

-like species, so that a maximum of

6

spectral lines can be produced of an electronic transition from the fifth excited state up to

n = 2

?

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 35

A particle

X

, moving with a certain velocity has a de-Broglie wavelength of

1 Å .

If a particle

Y

has a mass of

25 %

and velocity of

75 %

that of

X

, de-Broglie's wavelength of

Y

will be

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 36

The number of de Broglie waves formed in the fourth orbit of

H

are

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 37

Calculate the de Broglie wavelength of an electron in the ground state of the hydrogen atom, given that its kinetic energy is $13.6 eV .$ $(Mass of electron = 9.1 \times 10^{- 31} kg, charge on electron = 1.6 \times 10^{- 19} C)$