MEDIUM

11th West Bengal Board

IMPORTANT

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What will be the result of mixing $2 g$ of ice with $4 g$ of water at $45 ° C$ ?

Important Questions on Calorimetry and Change of State

MEDIUM

11th West Bengal Board

IMPORTANT

A Text Book of PHYSICS PART I : CLASS 11>Chapter 17 - Calorimetry and Change of State>EXERCISE>Q 15

A calorimeter of water-equivalent

30 g

contains

270 g

of water at

30 ° C . 10 g

of ice at

- 10 ° C

Is dropped into the calorimeter. Calculate the final temperature in

° C

of the mixture.

Sp

. Heat of ice.

= 0.5

And latent heat of fusion of ice

= 80 cal g^{- 1}

HARD

11th West Bengal Board

IMPORTANT

A Text Book of PHYSICS PART I : CLASS 11>Chapter 17 - Calorimetry and Change of State>EXERCISE>Q 16

Heat is supplied to a steady rate of

7

minutes to some amount of ice. For first one minute, the temperature of ice increased uniformly with time. Then the temperature remained steady for

4

minutes. During the last 2 minutes the temperature again increases at a uniform rate. Explain the above observations and calculate the final temperature. Latent heat of ice

= 80 cal / g

HARD

11th West Bengal Board

IMPORTANT

A Text Book of PHYSICS PART I : CLASS 11>Chapter 17 - Calorimetry and Change of State>EXERCISE>Q 17

69, 600

calories of heat are withdrawn from

100 g

of steam at

100 ° C

, what will be the result ? Latent heat of steam

= 540 cal / g

; Latent heat of ice

= 80 cal / g

HARD

11th West Bengal Board

IMPORTANT

A Text Book of PHYSICS PART I : CLASS 11>Chapter 17 - Calorimetry and Change of State>EXERCISE>Q 18

A calorimeter of water-equivalent

50 g

contains

250 g

of water and

200 g

of ice at

0 ° C

. If

200 g

of steam at

100 ° C

is passed through the calorimeter, what will be the total mass of water and its final temperature? Latent heat of ice

= 80 cal / g

; Latent heat of steam

= 540 cal / g

MEDIUM

11th West Bengal Board

IMPORTANT

A Text Book of PHYSICS PART I : CLASS 11>Chapter 17 - Calorimetry and Change of State>EXERCISE>Q 19

$1 g$ of steam at $100^{\circ} C$ and equal mass of ice at $0^{\circ} C$ are mixed. The temperature of the mixture in steady state will be (latent heat of steam $= 540 c a l / g$ , latent heat of ice $= 80 c a l / g$

EASY

11th West Bengal Board

IMPORTANT

A Text Book of PHYSICS PART I : CLASS 11>Chapter 17 - Calorimetry and Change of State>EXERCISE>Q 20

Temperature of a room is

15 ° C

and relative humidity is

100 %

. What is its dew point?

MEDIUM

11th West Bengal Board

IMPORTANT

A Text Book of PHYSICS PART I : CLASS 11>Chapter 17 - Calorimetry and Change of State>EXERCISE>Q 21

In a closed vessel there is some water mixed with watervapour at

27 ° C

. Total pressure of the mixture is

1.07 \times 10^{6} dyne {cm}^{- 2}

. At this temperature, vapour is just saturated. What will be the pressure in the vessel due to air only at

40 ° C

? What will be the total pressure in the vessel when temperature is reduced to

17 ° C

S . V . P

. at

17 ° C

and

27 ° C

are respectively

1.9 \times 10^{4}

and

3.7 \times 10^{4} dyne {cm}^{- 2}

MEDIUM

11th West Bengal Board

IMPORTANT

A Text Book of PHYSICS PART I : CLASS 11>Chapter 17 - Calorimetry and Change of State>EXERCISE>Q 22

Some ether is gradually introduced into the space above the mercury in a simple barometer tube until a little remains above the surface. The height of the mercury falls from

76 cm

36 cm

. What is the

S . V . P

. of ether at room temperature in

cm

Hg

What will be the result of mixing 2 g of ice with 4 g of water at 45°C?

Important Questions on Calorimetry and Change of State

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What will be the result of mixing $2 g$ of ice with $4 g$ of water at $45 ° C$ ?