HARD
JEE Main
IMPORTANT
Earn 100

When 800 mL of 0.5M nitric acid is heated in a beaker, its volume is reduced to half and 11.5 g of nitric acid is evaporated. The molarity of the remaining nitric acid solution is x×10-2M. (Molar mass of nitric acid is 63 g mol-1)

50% studentsanswered this correctly

Important Questions on Solutions

EASY
JEE Main
IMPORTANT
The elevation in boiling point for 1 molal solution of non-volatile solute A is 3 K. The depression in freezing point for 2 molal solution of A in the same solvent is 6 K. The ratio of Kb and Kf i.e., Kb/Kf is 1:X. The value of X is
MEDIUM
JEE Main
IMPORTANT
Boiling point of a 2% aqueous solution of a nonvolatile solute A is equal to the boiling point of 8% aqueous solution of a non-volatile solute B. The relation between molecular weights of A and B is.
HARD
JEE Main
IMPORTANT
When a certain amount of solid A is dissolved in 100 g of water at 25 °C to make a dilute solution, the vapour pressure of the solution is reduced to one-half of that of pure water. The vapour pressure of pure water is 23.76mmHg. The number of moles of solute A added is
MEDIUM
JEE Main
IMPORTANT
150 g of acetic acid was contaminated with 10.2 g ascorbic acid C6H8O6 to lower down its freezing point by x×10-1°C. The value of x is____ (Nearest integer). [Given Kf=3.9 K kg mol-1; Molar mass of ascorbic acid =176 g mol-1]
MEDIUM
JEE Main
IMPORTANT
A gaseous mixture of two substances A and B, under a total pressure of 0.8 atm is in equilibrium with an ideal liquid solution. The mole fraction of substance A is 0.5 in the vapour phase and 0.2 in the liquid phase. The vapour pressure of pure liquid A is____atm.(Nearest integer)
HARD
JEE Main
IMPORTANT
If O2 gas is bubbled through water at 303 K, the number of millimoles of O2 gas that dissolve in 1 litre of water is____(Nearest integer) (Given : Henry's Law constant for O2 at 303 K is 46.82k bar and partial pressure of O2=0.920 bar)
(Assume solubility of O2 in water is too small, nearly negligible)
HARD
JEE Main
IMPORTANT
1.80 g of solute A was dissolved in 62.5 cm3 of ethanol and freezing point of the solution was found to be 155.1 K. The molar mass of solute A is gmol-1. [Given: Freezing point of ethanol is 156.0 K. Density of ethanol is 0.80 g cm-3. Freezing point depression constant of ethanol is 2.00 K kg mol-1]
MEDIUM
JEE Main
IMPORTANT
In the depression of freezing point experiment
A. Vapour pressure of the solution is less than that of pure solvent
B. Vapour pressure of the solution is more than that of pure solvent
C. Only solute molecules solidify at the freezing point
D. Only solvent molecules solidify at the freezing point