When ${}^{24}\mathrm{Mg}$ is bombarded with neutron, a proton is ejected. Complete the equation and report the new element formed.

Write equations for the following transformation:

$\left(\mathrm{a}\right) {}_7{}^{14}\mathrm{N} (\mathrm{n}, \mathrm{p})$

$\left(\mathrm{b}\right) {}_{19}{}^{39}\mathrm{K} (\mathrm{n}, \mathrm{\alpha })$

Explain with reason the nature of emitted particle by:

$\left(\mathrm{a}\right) {}_{20}{}^{38}\mathrm{Ca}$

$\left(\mathrm{b}\right) {}_{18}{}^{35}\mathrm{Ar}$

$\left(\mathrm{c}\right) {}_{32}{}^{80}\mathrm{Ge}$

$\left(\mathrm{d}\right) {}_{20}{}^{40}\mathrm{Ca}$

For the given series reaction in ${\mathrm{n}}^{\text{th }}$ step, find out the number of produced neutrons and energy.

${}_{92}{}^{238}\mathrm{U}\to \mathrm{Ba}+\mathrm{Kr}+3_0{\mathrm{n}}^2+\text{Energy} \left(\mathrm{E}\right)$

${}_6{}^{11}\mathrm{C}$ on decay produces: