When phenol is treated with excess bromine water, what does it give?

The reaction of  with $\mathrm{HBr}$ gives

What is the major product $\mathrm{Y}$ in the above reaction?

Consider the following reaction:

$\mathrm{Phenol} \stackrel{\mathrm{Zn} \mathrm{dust}}{\to }\mathrm{X}\underset{\mathrm{Anhy}, {\mathrm{AlCl}}_3}{\overset{{\mathrm{CH}}_3\mathrm{Cl}}{\to }}\mathrm{Y} \stackrel{\mathrm{Alk}.{\mathrm{KMnO}}_4}{\to }\mathrm{Z}$

The product $\mathrm{Z}$ is

When phenol is heated with ${\mathrm{CHCl}}_3$ and alcoholic $\mathrm{KOH}$, salicylaldehyde is produced. This reaction is known as

In the following reaction, the product(s) formed is (are)

(i) $\mathrm{P}$ (major)

(ii) $\mathrm{Q}$ (minor)

(iii) $\mathrm{R}$ (minor)

(iv) $\mathrm{S}$ (major)