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When the momentum of a photon is changed by an amount p' then the corresponding change in the de-Broglie wavelength is found to be 0.20%. Then, the original momentum of the photon was

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Important Questions on Atoms, Molecules and Nuclei

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A proton and α-particle is accelerated through the same potential difference. The ratio of their de-Broglie wavelength will be
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A particle with rest mass m is moving with the speed of light c. The de-Broglie wavelength associated with it will be
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If the momentum of the electron is changed by P, then the de Broglie wavelength associated with it changes by 0.5%. The initial momentum of the electron will be
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In photoelectric effect, initially when energy of electrons emitted is E, de-Broglie wavelength associated with them is λ. Now, energy is doubled then associated de-Broglie wavelength λ' is
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Assertion: Photoelectric effect shows both the wave like and particle like behaviour of light.

Reason: Wave nature of matter is not visible in our daily observations.

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A proton and an α -particle are accelerated through the same potential difference. The ratio of de-Broglie wavelength of the proton to that of the α particle will be
 
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Particle wave has wavelength of the order of
 
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The de-Broglie wavelength of a particle with mass 1 g and velocity 100 m s-1 is