EASY
12th CBSE
IMPORTANT
Earn 100

When the voltage drop across a p-n junction diode is increased from 0.70 V to 0.71 V, the change in the diode current is 10 mA. What is the dynamic resistance of the diode?

Important Questions on Semiconductor Devices and Digital Circuits

MEDIUM
12th CBSE
IMPORTANT

The V-I characteristic of a silicon diode is as shown in figure. Calculate the resistance of the diode at

(i) I=15 mA and

(ii) V=-10 V

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MEDIUM
12th CBSE
IMPORTANT
A p-n junction is designed to withstand currents up to a maximum of 10 mA. A resistance of 200 Ω is connected in series with it. When forward biased, the diode has a potential drop of 0.5 V which is assumed to be independent of current. Find the maximum voltage of the battery to forward bias the diode.
EASY
12th CBSE
IMPORTANT

The silicon diode shown in figure is rated for a maximum current of 100 mA. Calculate the minimum value of resistor R. Assume the forward voltage drop across the diode to be 0.7 V.
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EASY
12th CBSE
IMPORTANT

Figure shows a diode connected to an external resistance and a battery. Assuming that the barrier developed in the diode is 0.5 V, obtain the value of current in the circuit in milliampere.
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EASY
12th CBSE
IMPORTANT

Find the current through the circuit and the potential difference across the diode shown in figure. The drift current for the diode is 20 μA.
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MEDIUM
12th CBSE
IMPORTANT

Find the equivalent resistance of the circuit shown in figure between points A and B, for

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EASY
12th CBSE
IMPORTANT

Assuming that the resistances of the meters are negligible, what will be the readings of the ammeters A1 and A2 in the circuit shown in figure?Question Image

EASY
12th CBSE
IMPORTANT
A potential barrier of 0.60 V exists across a p- n junction. (i) If the depletion region is 6.0×10-7 m thick, what is the intensity of the electric field in this region? (ii) If an electron with speed 5.0×105 ms-1 approaches the p-n junction from the n-side, with what speed will it enter the p-side? Mass of electron, m=9.1×10-31 kg, charge of the electron, e = 1.6×10-19