The nuclear radius of Al 13 27 is 3 . 6 fermi. Find the nuclear radius of Cu 29 64 .

Radius of Al is r Al = r ∘ A 1 3 = r ∘ 27 1 3 = 3 . 6 fermi, here A is atomic mass number corresponding to Al . For the radius of Cu is r Cu = r ∘ A 1 3 = r ∘ 64 1 3 . Now, r Cu r Al = 64 1 3 27 1 3 = 4 3 ⇒ r Cu = r Al × 4 3 = 4 . 8 fermi. Hence, the nuclear radius of Cu 29 64 is 4 . 8 fermi.

Match List (Experiment performed) with List - II (Phenomena discovered/associated)and select the correct option from the options given below the lists : List - I List - II (a) Davisson and germer experiment (i) Wave nature of electrons (b) Millikan's oil drop experiment (ii) Charge of an electron (c) Rutherford experiment (iii) Quantisation of energy levels (d) Franck - Hertz experiment (iv) Existence of nucleus

(a)-(i), (b)-(ii), (c)-(iv), (d)-(iii)

(a)- (iii), (b)-(iv), (c)-(i), (d)-(ii)

(a)-(iv),(b)-(iii),(c)-(ii),(d)-(i)

(a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)

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Important Questions on Nuclei

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The nuclear radius of

{}_{13}^{27}{Al}

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The mass number of a nucleus is,

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Physics>Modern Physics>Nuclei>Mass-energy and Nuclear Binding Energy

Match List (Experiment performed) with List - II (Phenomena discovered/associated)and select the correct option from the options given below the lists :

	List - I		List - II
(a)	Davisson and germer experiment	(i)	Wave nature of electrons
(b)	Millikan's oil drop experiment	(ii)	Charge of an electron
(c)	Rutherford experiment	(iii)	Quantisation of energy levels
(d)	Franck - Hertz experiment	(iv)	Existence of nucleus