Which figure represents the correct $\mathrm{F}.\mathrm{B}.\mathrm{D}.$ of the rod of mass m as shown in the figure:

  

Two blocks are in contact on a frictionless table. One has mass $m$ and the other $2m$. A force $F$ is applied on $2m$ as shown in the figure. Now the same force $F$ is applied from the right on $m$. In the two cases respectively, the ratio of force of contact between the two blocks will be 

Two forces of $6 \mathrm{N}$ and $3 \mathrm{N}$ are acting on the two blocks of $2 \mathrm{kg}$ and $1 \mathrm{kg}$ kept on frictionless floor. What is the force exerted on $2 \mathrm{kg}$ block by $1 \mathrm{kg}$ block?

A constant force $F$ is applied in horizontal direction as shown. Contact force between $M$ and $m$ is $N$ and between $m$ and $M^{\text{'}}$ is $N^{\text{'}}$ then

A mass $M$ is suspended by a rope from a rigid support at $A$ as shown in figure. Another rope is tied at the end $B$, and it is pulled horizontally with a force $F$. If the rope $AB$ makes an angle $\mathrm{\theta }$ with the vertical in equilibrium, then the tension in the string $AB$ is

In the system shown in the figure, the acceleration of the $1 \mathrm{kg}$ mass and the tension in the string connecting between $A$ and $B$ is:

A body of mass $8 \mathrm{kg}$ is hanging from another body of mass $12 \mathrm{kg}$. The combination is being pulled by a string with an acceleration of $2.2 \mathrm{m} {\mathrm{s}}^{–2}$. The tension $T_1$ and $T_2$ will be respectively: (use $g=9.8 \mathrm{m} {\mathrm{s}}^{-2}$)