Which of the following reactions will produce Schiff's base?

Product obtained in the following reaction is called

Product (C) obtained in the following sequence of reaction is

Consider the following reactions

a. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}\stackrel{\mathrm{Cu}(573 \mathrm{K})}{⟶}\mathrm{A}$

b. ${\mathrm{CH}}_3-\mathrm{CH}\left(\mathrm{OH}\right)-{\mathrm{C}}_2{\mathrm{H}}_5\stackrel{\mathrm{Cu}(573 \mathrm{K})}{⟶}\mathrm{B}$

Products $\mathrm{A}$ and $\mathrm{B}$ respectively are

Number of optically active products formed in following reaction is

${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{CHO}+\mathrm{HCN}\underset{(\mathrm{ii}) {\mathrm{H}}^{+}}{\overset{(\mathrm{i}) {\mathrm{OH}}^{-}}{\to }}$

Consider the reactions.

a. ${\mathrm{CH}}_3-\mathrm{CH}={\mathrm{CH}}_2\underset{\left(\mathrm{ii}\right){\mathrm{H}}_2{\mathrm{O}}_2/{\mathrm{OH}}^{-}}{\overset{\left(\mathrm{i}\right){\mathrm{BH}}_3/\mathrm{THF}}{\to }}\mathrm{A}\underset{(\mathrm{in} {\mathrm{CH}}_2{\mathrm{Cl}}_2)}{\overset{\mathrm{PCC}}{\to }}\mathrm{B}$

b. ${\mathrm{CH}}_3-\mathrm{CH}={\mathrm{CH}}_2\underset{\left(\mathrm{ii}\right){\mathrm{NaBH}}_4,\overline{\mathrm{O}}\mathrm{H}}{\overset{\left(\mathrm{i}\right)\mathrm{Hg}(\mathrm{OAc}{)}_2}{\to }}\mathrm{C}\underset{(\mathrm{in} {\mathrm{CH}}_2{\mathrm{Cl}}_2)}{\overset{\mathrm{PCC}}{\to }}\mathrm{D}$

Product $\mathrm{B}$ and $\mathrm{D}$ are

Consider the following reactions.

${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{COOH}\underset{\left(\mathrm{ii}\right){\mathrm{H}}_2\mathrm{O}}{\overset{(\mathrm{i}) {\mathrm{Br}}_2/Red\mathrm{P}}{\to }}\mathrm{A}.$ major product $\mathrm{A}$ is