Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 30

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Which of the following solutions has minimum buffer capacity?

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Important Questions on Equilibrium

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 31

The amount of sodium hydrogen carbonate, ${NaHCO}_{3}$ , in an antacid tablet is to be determined by dissolving the tablet in water and then titrating the resulting solution with hydrochloric acid. Which indicator is the most appropriate for this titration?

$\begin{array}{lc} Acid & K_{a} \\ H_{2} {CO}_{3} & 2.5 \times 10^{-} \\ {HCO}_{3} & 2.4 \times 10^{- 8} \end{array}$

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 32

The total number of different kinds of buffers obtained during the titration of

H_{3} {PO}_{4}

with

NaOH

are:

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 33

A

50 ml

sample of weak monobasic acid

HA

requires

100 ml

of

0.25 Ml NaOH

for complete neutralization. If the

ρH = 5

when

100 ml

of same.

NaOH

is added to

100 ml

of original sample of

HA

. then

{pK}_{a}

of

HA

is:

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 34

The solubility product of

AgCl

is

10^{- 10}

. What volume of water (in

L

) is required to dissolve

2.87 mg

of

AgCl

?

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 35

The solubility of

{CaF}_{2} (K_{sp} = 3.4 \times 10^{- 11})

in

0.1 M

solution of

NaF

would be

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 36

The solubility

Fe (OH)_{3}

will be maximum in:

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 37

The

pH

of a solution prepared by adding

1 mole

of

Mg (OH)_{2}

in

1 L

water is

(K_{sp} Mg (OH)_{2} = 1 \times 10^{- 11} \log (2.72 \times 10^{- 4}) = 3.57)

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 38

Solubility of

{As}_{2} S_{3}

in

10^{- 3} {MNa}_{2} S

solution, assuming no hydrolysis of cationic or anionic part is:

(K_{sp} {As}_{2} S_{3} = 16 \times 10^{- 27})

.