Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 131

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Which one of the following equations represent the motion of a body with finite constant non-zero acceleration. In these equations y denotes the displacement of the body at time $t$ and $a, b$ and $c$ are the constant of the motion

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Important Questions on Kinematics

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 132

A ball is thrown upward and reaches a height of

64

feet, its initial velocity should be

(g = 32 ft s^{- 2})

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 133

Two bodies of different masses

m_{a}

and

m_{b}

are dropped from two different heights

a

and

b

. The ratio of times taken by the two bodies to drop through these distance is :

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 134

A body thrown up with a finite speed is caught back after

4 s

. The speed of the body with which it is
thrown up is

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 135

A body is thrown upward and reaches its maximum height. At that position

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 136

The initial velocity of a particle (at

t = 0

) is

u

and the acceleration

f

of particle at time

t

is given by

f =

at. Where a is a constant which of the following relation for velocity

v

of particle after time

t

is true?

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 137

A body starting from rest and has uniform acceleration

8 m / \sec^{2} .

The distance travelled by it in

5 t h

second will be

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 138

A body starts from rest, the ratio of distances travelled by the body during

3 r d

and seconds is

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 139

The initial velocity of a particle is

10 m s^{- 1}

and its retardation is

2 m s^{- 2} .

The distance covered in the fifth second of the motion will be