White precipitate of $\mathrm{AgCl}$ dissolves in aqueous ammonia solution due to formation of

If ${\left[\mathrm{Cu}{\left({\mathrm{H}}_2\mathrm{O}\right)}_4\right]}^{2+}$ absorbs a light of wavelength $600 \mathrm{nm}$ for $\mathrm{d}-\mathrm{d}$ transition, then the value of octahedral crystal field splitting energy for ${\left[\mathrm{Cu}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6\right]}^{2+}$ will be____$\times {10}^{-21} \mathrm{J}$ [Nearest integer]

(Given : $\mathrm{h}=6.63\times {10}^{-34}\mathrm{Js}$ and $\mathrm{c}=3.08\times {10}^8{ \mathrm{ms}}^{-1}$)

Arrange the following coordination compounds in the increasing order of magnetic moments. (Atomic numbers: $\mathrm{Mn}=25;\mathrm{Fe}=26$)

A. ${\left[{\mathrm{FeF}}_6\right]}^{3-}$

B. ${\left[\mathrm{Fe}{\left(\mathrm{CN}\right)}_6\right]}^{3-}$

C. ${\left[{\mathrm{MnCl}}_6\right]}^{3-}$ (high spin)

D. ${\left[\mathrm{Mn}{\left(\mathrm{CN}\right)}_6\right]}^{3-}$

Choose the correct answer from the options given below

Given below are two statements :

Statement I: ${\left[\mathrm{Ni}{\left(\mathrm{CN}\right)}_4\right]}^{2-}$ is square planar and diamagnetic complex, with ${\mathrm{dsp}}^2$ hybridization for $\mathrm{Ni}$ but $\left[\mathrm{Ni}{\left(\mathrm{CO}\right)}_4\right]$ is tetrahedral, paramagnetic and with ${\mathrm{sp}}^3$ hybridication for $\mathrm{Ni}$.

Statement II : ${\left[{\mathrm{NiCl}}_4\right]}^{2-}$ and $\left[\mathrm{Ni}{\left(\mathrm{CO}\right)}_4\right]$ both have same d-electron configuration, have same geometry and are paramagnetic.

In light the above statements, choose the correct answer form the options given below