What is the de Broglie wavelength of a dust particle of mass 1 . 0 × 10 - 9 Kg drifting with a speed of 2 . 2 m / s ?

The mass of dust particle is, m = 1 × 1 0 - 9 kg The speed of the dust particle is, v = 2.2 m/s Hence, the de Broglie wavelength of the dust particle is, λ = h m v = 6 .6 × 10 − 34 1 × 10 − 9 2 .2 = 3 .0 × 10 − 25 m Here, the symbols have their usual meaning.

What is the de Broglie wavelength of a ball of mass 0 . 060 Kg moving at a speed of 1 . 0 m / s ?

The mass of ball is, m = 0.060 kg The speed of ball is, v = 1 . 0 m / s The Plank’s constant is, h = 6 . 6 × 1 0 - 34 Js . The de Broglie wavelength of the ball is, λ = h p . So, λ = h m v = 6 . 6 × 10 − 34 ( 0 . 060 ) ( 1 ) = 1 . 1 × 10 − 32 m . Therefore, the de Broglie's wavelength of this ball is 1 . 1 × 10 − 32 m . Here, the symbols have their usual meaning.