Write down first three terms of the sequence. First term Term-to-term rule 4 Multiply by 2 then add 1

Given, First term: 4 Term-to-term rule: Multiply by 2 then add 1 We have to write first three terms of the sequence: Write down the first term, which is 4 . Then use the term-to-term rule to work out the second term and third terms. Second term = 4 × 2 + 1 = 8 + 1 = 9 Third term = 9 × 2 + 1 = 18 + 1 = 19 Hence, first three terms of the sequence are 4 , 9 , 19 .

Write down first three terms of the sequence. First term Term-to-term rule 10 Subtract 8 then multiply by 6

Given, First term: 10 Term-to-term rule: Subtract 8 then multiply by 6 . We have to write first three terms of the sequence: Write down the first term, which is 10 . Then use the term-to-term rule to work out the second term and third terms. Second term = 10 - 8 × 6 = 2 × 6 = 12 Third term = 12 - 8 × 6 = 4 × 6 = 24 Hence, first three terms of the sequence are 10 , 12 , 24 .

Write down first three terms of the sequence. First term Term-to-term rule 24 Divide by 2 then add 4

Given, First term: 24 Term-to-term rule: Divide by 2 then add 4 . We have to write first three terms of the sequence: Write down the first term, which is 24 . Then use the term-to-term rule to work out the second term and third terms. Second term = 24 2 + 4 = 12 + 4 = 16 Third term = 16 2 + 4 = 8 + 4 = 12 Hence, first three terms of the sequence are 24 , 16 , 12 .

Match each first term to its sequence and its term-to-term rule. First term Sequence Term-to-term rule (A) 3 (a) 11 , 14 , 17 , 20 , . . . (i) subtract 2 (B) 80 (b) 17 , 15 , 13 , 11 , . . . (ii) divide by 2 (C) 64 (c) 3 , 6 , 12 , 24 , . . . (iii) multiply by 5 then add 1 (D) 11 (d) 80 , 40 , 20 , 10 , . . . (iv) multiply by 2 (E) 17 (e) 1 , 6 , 31 , 156 , . . . (v) divide by 2 then add 4 (F) 1 (f) 64 , 36 , 22 , 15 , . . . (vi) add 3

First term: 3 and Sequence: 3 , 6 , 12 , 24 , . . . We can see that the terms are getting multiplied by 2 every time, as 3 × 2 = 6 , 6 × 2 = 12 , 12 × 2 = 24 So, term-to-term rule is ‘multiply by 2 '. Thus, ( A ) → ( c ) → ( i v ) First term: 80 and Sequence: 80 , 40 , 20 , 10 , . . . We can see that the terms are getting divided by 2 every time, as 80 ÷ 2 = 40 , 40 ÷ 2 = 20 , 20 ÷ 2 = 10 So, term-to-term rule is ‘divide by 2 '. Thus, ( B ) → ( d ) → ( i i ) First term: 64 and Sequence: 64 , 36 , 22 , 15 , . . . We can see that the terms are getting divided by 2 then added with 4 every time, as 64 2 + 4 = 32 + 4 = 36 , 36 2 + 4 = 18 + 4 = 22 So, term-to-term rule is ‘divide by 2 then add 4 '. Thus, ( C ) → ( f ) → ( v ) First term: 11 and Sequence: 11 , 14 , 17 , 20 , . . . We can see that the terms are going up by 3 every time, as 11 + 3 = 14 , 14 + 3 = 17 , 17 + 3 = 20 So, term-to-term rule is ‘add 3 '. Thus, ( D ) → ( a ) → ( v i ) First term: 17 and Sequence: 17 , 15 , 13 , 11 , . . . We can see that the terms are going down by 2 every time, as 17 - 2 = 15 , 15 - 2 = 13 , 13 - 2 = 11 So, term-to-term rule is ‘subtract 2 '. Thus, ( E ) → ( b ) → ( i ) First term: 1 and Sequence: 1 , 6 , 31 , 156 , . . . We can see that the terms are getting multiplied by 5 then added with 1 every time, as 1 × 5 + 1 = 6 , 6 × 5 + 1 = 31 , 31 × 5 + 1 = 156 So, term-to-term rule is ‘multiply by 5 then add 1 '. Thus, ( F ) → ( e ) → ( i i i ) Hence, the matching of each first term to its sequence and its term-to-term rule is given below. First term Sequence Term-to-term rule (A) 3 (c) 3 , 6 , 12 , 24 , . . . (iv) multiply by 2 (B) 80 (d) 80 , 40 , 20 , 10 , . . . (ii) divide by 2 (C) 64 (f) 64 , 36 , 22 , 15 , . . . (v) divide by 2 then add 4 (D) 11 (a) 11 , 14 , 17 , 20 , . . . (vi) add 3 (E) 17 (b) 17 , 15 , 13 , 11 , . . . (i) subtract 2 (F) 1 (e) 1 , 6 , 31 , 156 , . . . (iii) multiply by 5 then add 1

MEDIUM

Lower Secondary Stage 7

IMPORTANT

Earn 100

Write down the missing terms of the finite sequence.

$90, 82,, 66,, 50,$

Important Questions on Sequences and Functions

MEDIUM

Lower Secondary Stage 7

IMPORTANT

Cambridge Lower Secondary Mathematics Learner's Book 7 Second Edition Digital Access>Chapter 9 - Sequences and Functions>Exercise 9.1>Q 4

Write down the missing terms of the finite sequence.

$8,,, 32, 40,,$

MEDIUM

Lower Secondary Stage 7

IMPORTANT

Cambridge Lower Secondary Mathematics Learner's Book 7 Second Edition Digital Access>Chapter 9 - Sequences and Functions>Exercise 9.1>Q 4

Write down the missing terms of the finite sequence.

$,, 28, 23,,, 8$

MEDIUM

Lower Secondary Stage 7

IMPORTANT

Cambridge Lower Secondary Mathematics Learner's Book 7 Second Edition Digital Access>Chapter 9 - Sequences and Functions>Exercise 9.1>Q 6

Write down first three terms of the sequence.

First term	Term-to-term rule
$4$	Multiply by $2$ then add $1$

MEDIUM

Lower Secondary Stage 7

IMPORTANT

Cambridge Lower Secondary Mathematics Learner's Book 7 Second Edition Digital Access>Chapter 9 - Sequences and Functions>Exercise 9.1>Q 6

Write down first three terms of the sequence.

First term	Term-to-term rule
$10$	Subtract $8$ then multiply by $6$

MEDIUM

Lower Secondary Stage 7

IMPORTANT

Cambridge Lower Secondary Mathematics Learner's Book 7 Second Edition Digital Access>Chapter 9 - Sequences and Functions>Exercise 9.1>Q 6

Write down first three terms of the sequence.

First term	Term-to-term rule
$24$	Divide by $2$ then add $4$

MEDIUM

Lower Secondary Stage 7

IMPORTANT

Cambridge Lower Secondary Mathematics Learner's Book 7 Second Edition Digital Access>Chapter 9 - Sequences and Functions>Exercise 9.1>Q 7

Match each first term to its sequence and its term-to-term rule.

First term	Sequence	Term-to-term rule
(A) $3$	(a) $11, 14, 17, 20, . . .$	(i) subtract $2$
(B) $80$	(b) $17, 15, 13, 11, . . .$	(ii) divide by $2$
(C) $64$	(c) $3, 6, 12, 24, . . .$	(iii) multiply by $5$ then add $1$
(D) $11$	(d) $80, 40, 20, 10, . . .$	(iv) multiply by $2$
(E) $17$	(e) $1, 6, 31, 156, . . .$	(v) divide by $2$ then add $4$
(F) $1$	(f) $64, 36, 22, 15, . . .$	(vi) add $3$

MEDIUM

Lower Secondary Stage 7

IMPORTANT

Cambridge Lower Secondary Mathematics Learner's Book 7 Second Edition Digital Access>Chapter 9 - Sequences and Functions>Exercise 9.1>Q 8

Sofia and Zara are looking at the sequence $4, 8, 20, 56, 164, . . .$

Sofia says: Term-to-term rule is 'Add $4$ '.

Zara says: Term-to-term rule is 'Multiply by $2$ '.

They are both incorrect. Explain why.

What must Sofia and Zara do to answer the question correctly?

MEDIUM

Lower Secondary Stage 7

IMPORTANT

Cambridge Lower Secondary Mathematics Learner's Book 7 Second Edition Digital Access>Chapter 9 - Sequences and Functions>Exercise 9.1>Q 9

In general, how many terms of a sequence must you know to be able to work out the term-to-term rule?

Write down the missing terms of the finite sequence. 90, 82, , 66, , 50,

Important Questions on Sequences and Functions

Learn and Prepare for any exam you want !

Write down the missing terms of the finite sequence.

$90, 82,, 66,, 50,$