Complete the equation: CH 3 - CHBr - CH 2 Br → Alc . KOH

When vicinal or 1 , 2 - dihalo compounds are treated with alcoholic potassium hydroxide, two molecules of hydrogen halides are eliminated from adjacent carbon atoms to give alkynes. CH 3 - CHBr - CH 2 Br → - HBr alc . KOH CH 3 - C Br = CH 2 → - HBr alc . KOH CH 3 - C ≡ CH

Complete the equation: R - C ≡ CH → ammoniacal AgNO 3

Alkyenes react with ammoniacal solution of silver nitrate (Tollen's reagent) to form a white precipitate. R - C ≡ CH + Ag NH 3 2 + OH - → R - C ≡ CAg + H 2 O + 2 NH 3 This reaction is a test to determine terminal alkyne group. This test does not hold true for internal multiple bond.

Complete the equation: HC ≡ CH + 2 Na → liq . NH 3

Acetylene and terminal alkynes react with sodamide i.e sodium in liquid ammonia, at 475 K to form disodium acetylide. This is an example of substitution reaction. HC ≡ CH + 2 Na → liq . NH 3 NaC ≡ CNa + NH 3

Complete the equation: R - C ≡ CH + HOCl →

Alkynes add two molecules of hypohalous acid in two steps forming a dihaloaldehyde in case of acetylene or dihaloketone in case of alkyl acetylene. The addition takes place according to Markownikoff's rule.

Complete the equation: CH 3 - C ≡ CH → HgSO 4 42 % H 2 SO 4

When propyne is passed over 42 % H 2 SO 4 at 60 ° C in the presence of HgSO 4 , an unstable compound vinyl alcohol is formed which further rearranges to form propanone. The addition takes place according to Markownikoff's rule. CH 3 - C ≡ CH → HgSO 4 42 % H 2 SO 4 [ CH 3 - C OH = CH 2 ] ⇌ CH 3 - C O - CH 3