Balance the following chemical equations: FeS + HCl → FeCl 2 + H 2 S

The given skeletal chemical equation is: FeS + HCl → FeCl 2 + H 2 S The necessary steps for balancing the given equation are as follows: Step I : On both the sides of the equation, the number of atoms of all the elements are counted. Reactant side Product side Fe = 1 Fe = 1 H = 1 H = 2 S = 1 S = 1 Cl = 1 Cl = 2 So, we can see that on the product side there is one extra hydrogen and one chlorine. Step II: First of all multiplication by 2 with HCl on the reactant side is done so, that the reaction becomes: FeS + 2 HCl → FeCl 2 + H 2 S So, we can now see that atoms on both the sides of the equation now become equal. Hence, the balanced equation according to the law of conservation of mass can be finally written as: FeS + 2 HCl → FeCl 2 + H 2 S

Balance the following chemical equations: Na 2 CO 3 + HCl → NaCl + H 2 O + CO 2

The given skeletal chemical equation is: Na 2 CO 3 + HCl → NaCl + H 2 O + CO 2 The necessary steps for balancing the given equation are as follows: Step I : On both the sides of the equation, the number of atoms of all the elements are counted. Reactant side Product side Na = 2 Na = 1 C = 1 C = 1 O = 3 O = 3 H = 1 H = 2 Cl = 1 Cl = 1 So, we can see that on the reactant side there is one extra sodium and one extra hydrogen on the product side. Step II: Now, multiplication by 2 with HCl on the reactant side and by 2 with NaCl on the product side is done so, that the reaction becomes: Na 2 CO 3 + 2 HCl → 2 NaCl + H 2 O + CO 2 So, we can now see that atoms on both the sides of the equation now become equal. Hence, the balanced equation according to the law of conservation of mass can be finally written as: Na 2 CO 3 + 2 HCl → 2 NaCl + H 2 O + CO 2

Balance the following chemical equations: H 2 + O 2 → H 2 O

The given skeletal chemical equation is: H 2 + O 2 → H 2 O The necessary steps for balancing the given equation are as follows: Step I : On both the sides of the equation, the number of atoms of all the elements are counted. Reactant side Product side H = 2 H = 2 O = 2 O = 1 So, we can see that on the reactant side one extra oxygen is present. Step II: Now, multiplication by 2 with H 2 on the reactant side and by 2 with H 2 O on the product side is done so, that the reaction becomes: 2 H 2 + O 2 → 2 H 2 O So, we can now see that atoms on both the sides of the equation now become equal. Hence, the balanced equation according to the law of conservation of mass can be finally written as: 2 H 2 + O 2 → 2 H 2 O