Modern's abc+ of Mathematics for Class 10>Chapter 8 - Introduction to Trigonometry>FOR ASSESSMENT>Q 7

EASY

10th CBSE

IMPORTANT

Earn 100

$\cos (90 ° - θ) =$

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Important Questions on Introduction to Trigonometry

EASY

10th CBSE

IMPORTANT

Modern's abc+ of Mathematics for Class 10>Chapter 8 - Introduction to Trigonometry>FOR ASSESSMENT>Q 8

If

\cos θ + \sec θ = \frac{5}{2}

, then

(\cos^{2} θ + \sec^{2} θ)

equals:

EASY

10th CBSE

IMPORTANT

Modern's abc+ of Mathematics for Class 10>Chapter 8 - Introduction to Trigonometry>FOR ASSESSMENT>Q 9

If

7 \tan θ = 4

, then

\frac{7 \sin θ - 3 \cos θ}{7 \sin θ + 3 \cos θ}

equals:

EASY

10th CBSE

IMPORTANT

Modern's abc+ of Mathematics for Class 10>Chapter 8 - Introduction to Trigonometry>FOR ASSESSMENT>Q 10

In the given figure $△ A B C$ is right angled at $C$ , $A B = 25 cm$ and $B C = 7 cm$ , then $\sin A$ equals:

Question Image

EASY

10th CBSE

IMPORTANT

Modern's abc+ of Mathematics for Class 10>Chapter 8 - Introduction to Trigonometry>FOR ASSESSMENT>Q 11

If

2 x = \sec A

and

\frac{2}{x} = \tan A

, then,

2 (x^{2} - \frac{1}{x^{2}})

equals:

MEDIUM

10th CBSE

IMPORTANT

Modern's abc+ of Mathematics for Class 10>Chapter 8 - Introduction to Trigonometry>FOR ASSESSMENT>Q 12

If

\tan θ = \frac{1}{\sqrt{7}}

, then

\frac{\cos e c^{2} θ - s e c^{2} θ}{\cos e c^{2} θ + s e c^{2} θ}

equals:

EASY

10th CBSE

IMPORTANT

Modern's abc+ of Mathematics for Class 10>Chapter 8 - Introduction to Trigonometry>FOR ASSESSMENT>Q 13

If

\cot θ = \frac{15}{8}

, then

\frac{(2 + 2 \sin θ) (1 - \sin θ)}{(1 + \cos θ) (2 - 2 \cos θ)}

equals:

EASY

10th CBSE

IMPORTANT

Modern's abc+ of Mathematics for Class 10>Chapter 8 - Introduction to Trigonometry>FOR ASSESSMENT>Q 14

Value of

(\sin 60 ° \cos 30 ° - \cos 60 ° \sin 30 °)

is

EASY

10th CBSE

IMPORTANT

Modern's abc+ of Mathematics for Class 10>Chapter 8 - Introduction to Trigonometry>FOR ASSESSMENT>Q 15

(\cos^{2} 30 ° \cos^{2} 45 ° + 4 \sec^{2} 60 ° + \frac{1}{2} \cos^{2} 90 ° - 2 \tan^{2} 60 °)

equals: