Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

EASY

Earn 100

what is a titrant?

Important Questions on Atoms, Molecules and Stoichiometry

EASY

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

Which of the following in aqueous solution is basic in character?

EASY

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

What is the weight of water in

1 litre

of

2 M NaCl

solution of density

1.117 g / mL

?

HARD

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

A weak acid (or base) is titrated against a strong base (or acid) and the volume V of a strong base (or acid) is plotted against the $pH$ of the solution (as shown in figure). The weak electrolyte (i.e. acid or base) could be:

Question Image

EASY

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

Molarity of

0.2 N H_{2} {SO}_{4}

is

HARD

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

A

100 mL

solution of

0.1 N HCl

was titrated with

0.2 N NaOH

solution. The titration was discontinued after adding

30 mL of NaOH

solution. The remaining titration was completed by adding

0.25 N KOH

. The volume of

KOH

required for completing the titration is

HARD

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

The volume of

0.25 M H_{3} {PO}_{3}

required to neutralise

25 mL

of

0.03 M Ca (OH)_{2}

is:

EASY

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

The mixture of

100 ml

of

0.5 (N) HCl

and

500 ml

of

0.1 (N) NaOH

is

EASY

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

_____

= \frac{number of moles of solute}{volume of solution in L} .

MEDIUM

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

The molarity of

0.56 L

of water vapour at

STP

is:

MEDIUM

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

Which of the following solutions have the same concentration?

EASY

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

5.0 L

of

0.4 M H_{2} {SO}_{4}

contains

HARD

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

The number of molecules in

100 mL

of

0.02 N H_{2} {SO}_{4}

is

HARD

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

50 mL

of a solution containing

1 g

each of

{Na}_{2} {CO}_{3}

,

NaHC 0_{3}

and

NaOH

was titrated with

1 N HCl

. What will be the titre reading when only phenolphthalein is used as the indicator?

EASY

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

A solution is a ____________ mixture.

EASY

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

The volume used for a definite amount of unknown reagent at its equivalence point is known as _____.

MEDIUM

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

The volume of $0.5 M H_{2} {SO}_{4}$ required to dissolve $0.5 g$ of copper $(II)$ carbonate $({CuCO}_{3})$ is:

MEDIUM

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

The normality of

500 ml

of

0.2 M

sulphuric acid is _____.

MEDIUM

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

The compound present in lesser amount, in a solution is called _____.

MEDIUM

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

The volume of water to be added to

100 {cm}^{3}

of

0.5 N

H_{2} {SO}_{4}

to get decinormal concentration is

MEDIUM

Chemistry>Physical Chemistry>Atoms, Molecules and Stoichiometry>Solutions and Concentrations

0.3 g

of an acid is neutralized by

40 {cm}^{3}

of

0.125 N

NaOH

. Equivalent mass of the acid is