Kohlrausch's Law and its Application

Form the following molar conductivities at infinite dilution,

$$\begin{gathered} {\wedge }_{\mathrm{m}}^{\circ } \mathrm{for} {\mathrm{Al}}_2{\left({\mathrm{SO}}_4\right)}_3=858 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1} \\ {\wedge }_{\mathrm{m}}^{\circ } \mathrm{for} {\mathrm{NH}}_4\mathrm{OH}=238.3 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1} \\ {\wedge }_{\mathrm{m}}^{\circ } \mathrm{for} {\left({\mathrm{NH}}_4\right)}_2{\mathrm{SO}}_4=238.4 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1} \end{gathered}$$

Calculate ${\wedge }_{\mathrm{m}}^{\circ }$ for $\mathrm{Al}{\left(\mathrm{OH}\right)}_3$

How is the molar conductivity of a weak electrolyte at infinite dilution determined?

Applying Kohlrausch law of independent migration of ions, write the expression to determine the limiting molar conductivity of calcium chloride

State Kohlrausch law of independent migration of ions.

The equivalent conductance at infinite dilution of the salt $\mathrm{MX}$ is $160.84 {\mathrm{ohm}}^{-1}{\mathrm{cm}}^2 {\mathrm{eq}}^{-1}$. If the transport number of ${\mathrm{M}}^{+}$ is $0.40$, calculate the ionic mobility of the ion.

The molar conductivity of acetic acid solution at infinite dilution is $390.7 {\mathrm{\Omega }}^{-1}{\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$. Calculate the molar conductivity of $0.01 \mathrm{M}$ acetic acid solution, given that the dissociation constant of acetic acid is $1.8\times {10}^{-5}$.
 

How does Kohlrausch's law help in the calculation degree of dissociation of a weak electrolyte?

Define Kohlrausch's law. How does it help in calculation of ${\mathrm{\lambda }}^{°}$ for a weak electrolyte?

Define Kohlrausch's law. How can it be used to find the degree of dissociation of a weak electrolyte?

Explain Kohlrausch law. (Definition and Formula)

Conductivity of $0.00241 \mathrm{M}$ acetic acid solution is $7.896\times {10}^{-5} \mathrm{S} {\mathrm{cm}}^{-1}$. Calculate its molar conductivity in this solution. If ${\mathrm{\Lambda }}_{\mathrm{m}}^{°}$ for acetic acid be $390.5 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$, what would be its dissociation constant?

The molar conductivity of acetic acid at infinite dilution is $387 \mathrm{S} {\mathrm{m}}^2 {\mathrm{mol}}^{-1}$.  At the same temperature, but at a concentration of $1$ mole in $1000$ litres, it is $55 \mathrm{S} {\mathrm{m}}^2 {\mathrm{mol}}^{-1}$. What is the $\%$ age dissociation of $0.001 \mathrm{M}$ acetic acid.

If the molar conductivity of a given acetic acid solution is $48.5 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$ at $25 °\mathrm{C}$, calculate the degree of dissociation of acetic acid at this temperature.

${\mathrm{\Lambda }}_{\mathrm{m}}^{°}\left(\mathrm{HCl}\right)=379.4 {\mathrm{\Omega }}^{-1}{\mathrm{cm}}^2{\mathrm{mol}}^{-1}; {\mathrm{\Lambda }}_{\mathrm{m}}^{°}\left(\mathrm{KCl}\right)=130.1 {\mathrm{\Omega }}^{-1}{\mathrm{cm}}^2{\mathrm{mol}}^{-1}; {\mathrm{\Lambda }}_{\mathrm{m}}^{°}\left({\mathrm{CH}}_3\mathrm{COOK}\right)=95.6 {\mathrm{\Omega }}^{-1}{\mathrm{cm}}^2{\mathrm{mol}}^{-1}.$

The molar conductivities at infinite dilution of potassium chloride, hydrochloric acid and potassium acetate are $130.1, 379.4$ and $95.6 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$respectively. Calculate the value of molar conductivity infinite dilution for acetic acid.

If the molar conductivities at infinite dilution at $293 \mathrm{K}$ for aqueous hydrochloric acid, sodium acetate and sodium chloride solution are $383.5, 78.4$ and $102.0 \mathrm{S} {\mathrm{cm}}^2$ respectively, calculate the molar conductivity acetic acid at this temperature and dilution. If the molar conductivity of acetic acid at some other dilution is $100.0 \mathrm{S} {\mathrm{cm}}^2$ at $293 \mathrm{K}$, calculate the degree of ionization of acetic acid at this dilution.

The ${\mathrm{\Lambda }}_{\mathrm{m}}^{°}$ values for $\mathrm{NaCl}$ and $\mathrm{KCl}$ are $126.5$ and $149.9 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$ respectively. The ionic conductances of ${\mathrm{Na}}^{+}$ at infinite dilution is $50.1 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$. Calculate the ionic conductance at infinite dilution for ${\mathrm{K}}^{+}$ ion.

Find out the molar conductivity of an aqueous solution of ${\mathrm{BaCl}}_2$ at infinite dilution when ionic conductances of ${\mathrm{Ba}}^{2+}$ and ${\mathrm{Cl}}^{-}$ ion are $127.30 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$ and $76.34 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$ respectively.

Given molar conductivities at infinite dilution for,

$$\begin{gathered} {\mathrm{\Lambda }}_{\mathrm{m}}^{°}\left(\mathrm{Ba}{\left(\mathrm{OH}\right)}_2\right)=517.6 {\mathrm{\Omega }}^{-1}{\mathrm{cm}}^2{\mathrm{mol}}^{-1}. \\ {\mathrm{\Lambda }}_{\mathrm{m}}^{°}\left({\mathrm{BaCl}}_2\right)=240.6 {\mathrm{\Omega }}^{-1}{\mathrm{cm}}^2{\mathrm{mol}}^{-1}. \\ {\mathrm{\Lambda }}_{\mathrm{m}}^{°}\left({\mathrm{NH}}_4\mathrm{Cl}\right)=129.8 {\mathrm{\Omega }}^{-1}{\mathrm{cm}}^2{\mathrm{mol}}^{-1}. \end{gathered}$$

Calculate ${\mathrm{\Lambda }}_{\mathrm{m}}^{°}\left({\mathrm{NH}}_4\mathrm{OH}\right)$.

Calculate the molar ionic conductance of ${\mathrm{Al}}^{3+}$ ions at infinite dilution, given that the molar conductance of ${\mathrm{Al}}_2{\left({\mathrm{SO}}_4\right)}_3$ and molar ionic conductance of ${\mathrm{SO}}_4^{2-}$ ions at infinite dilution are $858 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$ and $160 \mathrm{S} {\mathrm{cm}}^2 {\mathrm{mol}}^{-1}$ respectively.

Which of the following expressions correctly represents the equivalent conductance at infinite dilution of ${\mathrm{Al}}_2{\left({\mathrm{SO}}_4\right)}_3$. Given that ${{\mathrm{\lambda }}^0}_{{\mathrm{Al}}^{3+}}$ and ${{{\mathrm{\lambda }}^0}_{{\mathrm{SO}}_4}}^{2-}$ are the equivalent conductances at infinite dilution of the respective ions?