Equations Reducible to a Pair of Linear Equations in Two Variables

Solve $\frac{2}{\sqrt{x}}+\frac{3}{\sqrt{y}}=2;\frac{4}{\sqrt{x}}-\frac{9}{\sqrt{y}}=-1$

Solve:

 $3x-\frac{2}{y}=5$; $x+\frac{4}{y}=4$

Solve: $\frac{2}{x}+\frac{{\displaystyle 5}}{y}=1; \frac{3}{x}+\frac{2}{y}=\frac{19}{30}$

Solve:

$\frac{3}{\sqrt{x}}+\frac{4}{\sqrt{y}}=2$

$\frac{5}{\sqrt{x}}+\frac{7}{\sqrt{y}}=\frac{41}{12}$

Solve the following pair of linear equations:

$\frac{2}{x-1}-\frac{1}{y-2}=1, \frac{4}{x-1}+\frac{3}{y-2}=8$

If $3x-\frac{1}{4y}=24$, then the value of $8x\left(6x-\frac{1}{y}\right)+\frac{1}{12y^2}(4-3y+36x{y}^2)$ $($ where $y\ne 0)$ is

Solve: 

$\frac{5}{3}x-\frac{3}{2}y=-2$

$\frac{1}{2}y-\frac{3}{4}x=3$

Solve the following equations for $x$ and $y$.

$$\begin{gathered} \frac{44}{x+y}+\frac{30}{x-y}=10 \\ \frac{55}{x+y}+\frac{40}{x-y}=13 \end{gathered}$$

$\frac{2}{x}-\frac{4}{y}=8$

$\frac{1}{x}-\frac{7}{2y}=5$

Solve this linear equation by elimination method.

Solve: $\frac{44}{x+y}+\frac{30}{x-y}=10, \frac{55}{x+y}+\frac{40}{x-y}=13$

Based on equations reducible to linear equations. Solve for $x$ and $y$.

$\frac{11}{2x}-\frac{9}{2y}=-\frac{23}{2}; \frac{3}{4x}+\frac{7}{15y}=\frac{23}{6}$

Solve the following system of equations

$\frac{5}{x-1}+\frac{1}{y-2}=2$

$\frac{6}{x-1}-\frac{3}{y-2}=1$

Solve:

$4y-x=2$

$\frac{x+2y}{2x+y}=\frac{4}{5}$

Reduce the given equations into standard form of linear equation.

$$\begin{gathered} \frac{11}{x-1}+\frac{12}{y-2}=21 \\ \frac{14}{x-1}+\frac{15}{y-2}=24 \end{gathered}$$

Which equation can be reduce to pair of linear equation?

The general solution in positive integers, and the least values of $x$ and $y$ which satisfy the equation $6x-13y=1$ are

The value of $x$ obtained on solving the following

equations: $\frac{m}{x}-\frac{n}{y}=a$ and $\frac{m}{x}+\frac{n}{y}=b$ is 

Which of the following pairs of equations can be solved by reducing them as linear equations?