Frustum of a Cone

Slant height of the cone is smaller than the height of the cone.

The radius of circular top and base of frustum are $5 \mathrm{cm}$ and $7 \mathrm{cm}$, respectively. If the height of frustum is $11 \mathrm{cm}$, then find the total surface area of frustum.

The radius of circular top and base of frustum are $7 \mathrm{cm}$ and $3 \mathrm{cm}$, respectively. If the slant height of frustum is $11 \mathrm{cm}$, then find the total surface area of frustum.

The radius of circular top and base of frustum are $7 \mathrm{cm}$ and $3 \mathrm{cm}$, respectively. If the slant height of frustum is $11 \mathrm{cm}$, then find the curved surface area of frustum.

When the smaller end, parallel to the base is cut from a cone, the shape we get is called the frustum of the cone.

When the smaller end, _____ to the base is cut from a cone, the shape we get is called the frustum of the cone.

An oil funnel made of tin sheet consists of a 10cm long cylindrical portion attached to a frustum of a cone. If the total height is 22cm, diameter of the cylindrical portion is 8cm and diameter of the top of the funnel is 18cm. Find area of tin sheet required to make the funnel. Take $\pi =3.14$

The height of a cone is 40 cm. A small cone is cut off at the top by a plane parallel to the bases. It the volume of the small cone be $\frac{1}{64}$ of the volume of the given cone, at what height above the base is the section made

A bucket is in the form of a frustum of a cone, depth is 15 cm and the diameters of the top and the bottom are 56 cm and 42 cm respectively. Find how many liters of water can the bucket hold ? $\left(\text{Take }\pi =\frac{22}{7}\right)$

A reservoir is in the shape of a frustum of a right circular cone. It is 8 m across at the top and 4 m across at the bottom. If it is 6 m deep its capacity is :

If the radii of the circular ends of a bucket of height 40 cm are 35 cm and 14 cm respectively, then the volume of the bucket in cubic centimeters is :

A cone is cut half way through its axis and parallel to the base, the volumes of two portions are in the ratio