Equilibrium of a Particle

The forces, which meet at one point but their lines of action do not lie in one plane, are called:-

A block of mass $5$ $\mathrm{kg}$ is suspended by a massless rope of length $2$ $\mathrm{m}$ from the ceiling. A force of $50$ $\mathrm{N}$ is applied in the horizontal direction at the midpoint $P$ of the rope, as shown in the figure. The angle made by the rope with the vertical in equilibrium is: (Take$g=10\mathrm{ }\mathrm{m}\mathrm{ }{\mathrm{s}}^{-2}$)

There are four force acting at a point $P$ produced by strings as shown in figure, which is at rest. The force $F_1$ and $F_2$ are

Three charges $–q_1$, $q_2$ and $–q_3$ are placed as shown in the figure. The $x$-component of the force on $–q_1$ is proportional to

A body of mass $m$ is suspended by two strings making angle $\alpha$ and $\mathrm{\beta }$ with the horizontal as shown in figure. Tensions in the two strings are

Four concurrent coplanar forces in Newton are acting at a point and keep it in equilibrium figure. Then values of $F$ and $\theta$ are angle made by $1\mathrm{N}$ with the plane is $60$