De Morgan’s theorem - Laws and theorems of Boolean Algebra

The same input signal is applied to both the (input) terminals of a given logic gate.

If the output is the(i) same as the (common) input signal

(ii) inverted with respect to the (common) input signal,

Identify the logic gate/s involved in each case.

What is the use of De Morgan's theorem?

In the given circuit, the input voltages at $\mathrm{P}$ and $\mathrm{Q}$ could be either $0 \mathrm{V}$ or $10 \mathrm{V}$. Use the fact that a diode under forward bias is a short circuit, and under reverse bias is an open circuit. The truth table of the circuit will be that of

To get output $y=1$ in given circuit, which of the following input will be correct?

Truth table for the given circuit is

Which logic gate is represented by the following combination of logic gates?

Which logic gate with inputs $A$ and $B$ performs the same operation as that performed by the following circuit?

The logic circuit shown below has the input waveforms $A$ and $B$ as shown in the figure. Pick out the correct output waveform.

The output $Y$ of the given logic circuit is,

In the following combinations of logic gates, the output of $A, B$ and $C$ are respectively

Following diagram performs logic function of 

In the following combinations of logic gates, the outputs $A, B$ and $C$ are respectively :-

In the following circuit, the output for $Y$all possible inputs $A$ and $B$ is expressed by the truth
table :-

Output $C$ of the network shown is:-

Derive the Boolean expression for the output for the gate circuit shown below in the figure.

In the circuit $A, B$ represents two inputs and $C$ represents the output. Then which logic operation is represented by the circuit,

Given $\mathrm{X}=(\overline{\mathrm{A}}+\overline{\mathrm{B}})$ AB. Then the output column $\left(\mathrm{X}\right)$ in the truth table will be

To get an output $1$ from the circuit shown in the figure, the input must be

What is the Boolean equation for the figure?

In the given circuit, the binary inputs at $A$ and $B$ are both $1$ in one case and both $0$ in the next case. The respective outputs at $Y$ in these two cases will be