Compound Microscope

The expression for magnifying power of compound microscope is

The focal lengths of the objective and the eye piece of a compound microscope are $2.0 \mathrm{cm}$ and $3.0 \mathrm{cm},$ respectively. The distance between the objective and the eye piece is $15.0 \mathrm{cm}.$ The final image formed by the eye piece is at infinity. The two lenses are thin. The distance in $\mathrm{cm}$ of the object and the image produced by the objective, measured from the objective lens, are respectively

What is the relation between visual angle and apparent size.

Define visual angle. 

What is the relation between visual angle and Apparent size

What is the unit of visual angle.

What angle subtended is the minimal visual acuity

Is a microscope eyepiece always 10x?

In a compound microscope, the objective and eyepiece have focal length of $0.95 \mathrm{cm}$ and $5 \mathrm{cm}$, respectively and are kept at a distance of $20 \mathrm{cm}$. The final image produced by this compound microscope is at a distance of $25 \mathrm{cm}$ from eyepiece. The total magnification is

The focal length of the objective of a microscope is

In $\mathrm{a}$ compound microscope the focal length of objective lens is $1.2 \mathrm{cm}$ and focal length of eye piece is $3.0 \mathrm{cm}.$ When object is kept at $\text{1.25 cm}$
in front of objective, final image is formed at infinity. Magnifying power of the compound microscope should be :

In a compound microscope, if the objective produces an image $I_0$ and the eyepiece produces an image $I_{\mathrm{e}}$, then choose correct statement:

How can you differentiate between a compound microscope and a telescope just by looking at it? 

Final image obtained from a compound microscope is-

Final image obtained from a compound microscope is -

A compound microscope consists of an objective lens with focal length $20 \mathrm{c}\mathrm{m}$ the magnification will be

The objective lens and eye piece lens of a compound microscope have focal lengths 1.5 cm and 5 cm respectively. The object is placed at a distance 1.8 cm. What is its magnification?  ( Take the least distance of distinct vision = 24 cm)

A microscope is having an objective of focal length $1 \mathrm{cm}$ and eyepiece of focal length $6 \mathrm{cm}$. If tube length is $30 \mathrm{cm}$ and the image is formed at the least distance of distinct vision, what is the magnification produced by the microscope? (Take $\mathrm{D}=25 \mathrm{cm}$)

A compound microscope has an eye piece of  focal length 10 cm and an objective of focal length of 4 cm. Calculate the magnification, if an object is kept at a distance of 5 cm from the objective then final image is formed at the least distance of distinct vision