Selective Discharge of Ions

The standard reduction potential values of three metallic cations, X, Y and Z are $0.52,-3.03 \mathrm{and}-1.18\mathrm{V}$ respectively. The order of reducing power of the corresponding metals is:

${\mathrm{H}}_2$ cannot be displaced by

The standard electrode potential of ${\mathrm{M}}^{2+}/\mathrm{M}$ is positive for

Lower the position of an ion in an electrochemical series more easily it will get discharged at the respective electrode.

How does nature of electrode affect selective discharge of ions.

If a solution contains more than two cations and anions, the selective discharge of ions depends on electrochemical series.

Define selective discharge of ions.

Select the correct option, for the given standard ${\mathrm{E}}^{\mathrm{o}}$ values of few redox couples:
$\mathrm{Z}{\mathrm{n}}^{2+}/\mathrm{Z}\mathrm{n}=-0.76\mathrm{V}, \mathrm{A}{\mathrm{g}}^{+}/\mathrm{A}\mathrm{g}=+0.80\mathrm{V}, {\mathrm{Cu}}^{2+}/\mathrm{Cu}=0.34\mathrm{V}$
 

Mark the correct statement based on the ${\mathrm{E}}^{\mathrm{o}}$ values of redox couple of halogens given below
$\mathrm{ }{{\mathrm{E}}^{\mathrm{o}}}_{{\mathrm{I}}_2/{\mathrm{I}}^{-}}=+0.54\mathrm{V},{{\mathrm{E}}^{\mathrm{o}}}_{{\mathrm{Br}}_2/{\mathrm{Br}}^{-}}=+1.08\mathrm{V};{{\mathrm{E}}^{\mathrm{o}}}_{{\mathrm{Cl}}_2/{\mathrm{Cl}}^{-}}=+1.36\mathrm{V}$.

Which element can reduce Aluminium?

Out of which of the following statements is true- 

Given the reduction potential data as-  ${\mathrm{E}}_{{\mathrm{Ag}}^{+}/\mathrm{Ag}}^{\mathrm{o}}=+0.8\mathrm{ }\mathrm{V},\mathrm{ }{\mathrm{E}}_{{\mathrm{Ni}}^{+2}/\mathrm{Ni}}^{\mathrm{o}}=-\mathrm{ }0.25\mathrm{ }\mathrm{V}\mathrm{ }$ .

Among the following, which is the most reactive metal which displaces other metals from their salts in solution?

${\mathrm{E}}_{\mathrm{Z}\mathrm{n}/\mathrm{Z}{\mathrm{n}}^{2+}}^0=+0.76\mathrm{V},\mathrm{ }{\mathrm{E}}_{\mathrm{A}\mathrm{g}/\mathrm{A}{\mathrm{g}}^{+}}^0=-0.80\mathrm{V},\mathrm{ }$

${\mathrm{E}}_{\mathrm{C}\mathrm{u}/\mathrm{C}{\mathrm{u}}^{2+}}^0=-0.34\mathrm{V},\mathrm{ }{\mathrm{E}}_{\mathrm{C}\mathrm{o}/\mathrm{C}{\mathrm{o}}^{+2}}^0=0.28\mathrm{V}$

We have taken two electrode, with potential values: ${\mathrm{E}}_{{\mathrm{Mg}}^{2+}/\mathrm{Mg}}^{\mathrm{a}}=- 2.37 \mathrm{V} \mathrm{and} {{\mathrm{E}}^{\mathrm{b}}}_{{\mathrm{Fe}}^{3+}/\mathrm{Fe} }=-0.04 \mathrm{V}$. Which of the following will act as the best reducing agent:

Identify the correct order of the metals in which they displace each other from solution of their salts:

Which of the following can not displace ${\mathrm{H}}_2$?

The decreasing order of reducing power of P, Q, R, S whose reduction potential are $-2.90, +0.34, +1.20$ and $-0.76$, is

The more reactive the metal, the less likely the metal ions are to be discharged preferentially at the _____ during electrolysis.