Saleha Pervez and Vandana Solutions for Chapter: Electrochemistry, Exercise 5: Chapter Practice

Author:Saleha Pervez & Vandana

Saleha Pervez Chemistry Solutions for Exercise - Saleha Pervez and Vandana Solutions for Chapter: Electrochemistry, Exercise 5: Chapter Practice

Attempt the practice questions on Chapter 3: Electrochemistry, Exercise 5: Chapter Practice with hints and solutions to strengthen your understanding. All In One ISC Chemistry Class 12 solutions are prepared by Experienced Embibe Experts.

Questions from Saleha Pervez and Vandana Solutions for Chapter: Electrochemistry, Exercise 5: Chapter Practice with Hints & Solutions

MEDIUM
12th ICSE
IMPORTANT

The incorrect statement about electrochemistry is:

EASY
12th ICSE
IMPORTANT

Zn(s)+Cu2+(aq)Zn2+(aq)+Cu(s). The above redox reaction is used in

MEDIUM
12th ICSE
IMPORTANT

For the generation of electrode potential of 1.1 V, the ideal concentration of zinc and copper ion (in mol dm-3 ) in the galvanic cell is
 

MEDIUM
12th ICSE
IMPORTANT

Compound XA, XB, XC are added into separate test tubes containing A, B, C solutions. XB react with A and C. XA does not react with any of these. XC reacts with A. Which of the following is the correct decreasing order for the oxidation of the anions?

MEDIUM
12th ICSE
IMPORTANT

Select the strongest reducing agent from the given electrode potential.

EASY
12th ICSE
IMPORTANT

Two electrolytic cells containing silver nitrate solution and dilute sulphuric acid were connected in a series. A steady current of 2.5 A was passed through them till 1.078 g of silver was deposited (Ag = 107.8 g/mol). What is the weight of oxygen gas liberated during the reaction?
 

MEDIUM
12th ICSE
IMPORTANT

How many moles of Hg will be produced by electrolysing 1.0 M Hg(NO3)2 solution with a current of 2.00 A for 3 hours?

 [Hg(NO3)2= 200.6 g/mol] 

HARD
12th ICSE
IMPORTANT

Iron may be protected from rusting by coating with zinc or tin. By referring to the data given below, explain why zinc protects iron more effectively than tin? Zn2++ 2e-  Zn, E° = -0.76 V; Fe2++2e-Fe, E°= - 0.44 V; Sn2++ 2e-Sn, E°=-0.14 V.