Embibe Experts Solutions for Chapter: Trigonometric Equations and Inequalities, Exercise 2: Exercise-2

$\sin x-{\cos }^{2}x-1$ assumes the least value for the set of values of $x$ given by

The general solution of the equation $\cos x·\cos 6x=-1$ is 

Which of the following set of values of $x$ satisfies the inequation $\sin 3x<\sin x$?

The equation $2\sin \frac{x}{2}·{\cos }^{2}x+{\sin }^{2}x=2\sin \frac{x}{2}·{\sin }^{2}x+{\cos }^{2}x$ has a root for which

$\cos 15x=\sin 5x$ if

$5{\sin }^{2}x+\sqrt{3}\sin x\cos x+6{\cos }^{2}x=5$ if

${\sin }^{2}x+2\sin x\cos x-3{\cos }^{2}x=0$ if

Solution set of inequality ${\sin }^{3}x\cos x>{\cos }^{3}x\sin x,$ where $x\in \left(0, \pi \right)$, is