Embibe Experts Solutions for Chapter: Capacitance, Exercise 1: Exercise-1

Two parallel plates capacitors of value $C$ and $2C$ are connected in parallel and are charged to a potential difference $V.$ If now battery is disconnected and a medium of dielectric constant $K$ is introduced between the plates of the capacitor $C,$ then the potential difference between the capacitors plates will become-

As shown in the figure half the space between plates of a capacitor is filled with an insulator material of dielectric constant $K,$ if initial capacity was $C$ then the new capacity is, 

Two materials of dielectric constant $k_1$ and $k_2$ are filled between two parallel plates of a capacitor as shown in the figure. The capacity of the capacitor is:

After charging a capacitor the battery is removed. Now by placing a dielectric slab between the plates

A parallel plate capacitor is filled with two dielectrics as shown in figure. If $A$ is area of each plate, then the effective capacitance between $X$ and $Y$ is

An insulator plate is passed between the plates of a capacitor. Then current

In the adjoining diagram, two geometrically identical capacitors $A$ and $B$ are connected to a battery. Air is filled between the plates of $C_1$ and a dielectric is filled between the plates of $C_2,$ then

The electric field between two parallel plates of a capacitor is $2.1\times {10}^{-5}{\mathrm{NC}}^{-1}$. If a medium is inserted between the plates than the electric field becomes $10\times {10}^{-5}{\mathrm{NC}}^{-1}$. Now, the value of dielectric will be