Embibe Experts Solutions for Chapter: Electromagnetic Induction, Exercise 1: Exercise-1

A thin wire is bent to form a square loop $ABCD.$ A battery of e.m.f $2 \mathrm{V}$ is connected between the points $A$ and $C.$ The magnetic induction due to the current in the loop at centre $O$ will 

An inductor $\left(L=100 \mathrm{mH}\right)$, a resistor $\left(R=100 \mathrm{\Omega }\right)$ and a battery $\left(E=100 \mathrm{V}\right)$ are initially connected in series as shown in the figure. After a long time, the battery is disconnected after short-circuiting the points $A$ and $B$. The current in the circuit, $1$ $\mathrm{ms}$ after the short circuit is:

The unit of mutual inductance is-

The self-inductances of two identical coils are $0.1 \mathrm{H}$.They are wound over each other. Mutual inductance will be -

Two conducting loops of radi $R_1$ and $R_2$ are concentric and are placed in the same plane. If $R_1>>R_2$, the mutual inductance M between them will be directly proportional to-

Two inductance coils of inductance $L_1$ and $L_2$ are kept at a sufficiently large distance apart. On connecting them in parallel their equivalent inductance will be

Two circular coils can be arranged in any of the three situations shown in the figure. Their mutual inductance will be:

A long solenoid has $500$ turns. When a current of $2 \mathrm{A}$ is passed through it, the resulting magnetic flux linked with each turn of the solenoid is $4\times {10}^{-3}$ Wb. The self-inductance of the solenoid is