Embibe Experts Solutions for Chapter: Friction, Exercise 2: Exercise-2

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Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Chapter: Friction, Exercise 2: Exercise-2

Attempt the practice questions on Chapter 6: Friction, Exercise 2: Exercise-2 with hints and solutions to strengthen your understanding. Alpha Question Bank for Medical: Physics solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Friction, Exercise 2: Exercise-2 with Hints & Solutions

MEDIUM
NEET
IMPORTANT

Two blocks m1=4 kg and m2=2 kg are connected by a weightless rod on a plane having inclination of 37°. The coefficient of dynamic friction of m1 and m2 with the inclined plane are, μ=0.25. Then, the common acceleration of the two blocks and the tension in the rod are,

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MEDIUM
NEET
IMPORTANT

A force F=t is applied to block A as shown in the figure. The force is applied at t=0 seconds when the system was at rest and string is just straight without tension. Which of the following graphs gives the force between B and horizontal surface as a function of time t.

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HARD
NEET
IMPORTANT

If the coefficient of friction between A and B is μ1 the maximum horizontal acceleration of the wedge A for which B will remain at rest with respect to the wedge is:

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EASY
NEET
IMPORTANT

What is the minimum stopping distance for a vehicle of mass m moving with speed v along a level road if the coefficient of friction between the tyres and the road is μ?

MEDIUM
NEET
IMPORTANT

A block of mass m1=1 kg another mass m2=2 kg are placed together (see figure) on an inclined plane with the angle of inclination θ. Various values θ are given in List I. The coefficient of friction between the block m1 and the plane is always zero. The coefficient of static and dynamic friction between the block m2 and the plane is equal toμ=0.3. In Listll, an expression for the friction on block m2 given. Match the correct expression of the friction in List II with the angles given in List 1 and choose the correct option. The acceleration due to gravity is denoted by g [useful information: tan5.5°0.1; tan11.5°0.2; tan16.5°0.3]

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List I List II
P. θ=5° 1. m2gsinθ
Q. θ=10° 2. m1+m2gsinθ
R. θ=15° 3. um2gcosθ
S. θ=20° 4. μm1+m2gcosθ

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EASY
NEET
IMPORTANT

Assertion: While drawing a line on a paper, friction force acts on paper in the same direction along which line is drawn on the paper.

Reason: Friction always opposes motion.

EASY
NEET
IMPORTANT

Assertion: A man and a block rest on smooth horizontal surface. The man holds a rope which is connected to block. The man cannot move on the horizontal surface.

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Reason: A man standing at rest on smooth horizontal surface can start walking due to absence of friction (the man is only in contact with floor as shown).

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MEDIUM
NEET
IMPORTANT

Assertion : A block of mass m kg is kept on rough fixed horizontal surface as shown. The coefficient of friction between block and horizontal surface is μ=0.1. Then the magnitude of minimum horizontal force required to move the block is m Newton (Take g=10 m/s2 )

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Reason : A block is kept on fixed rough horizontal surface. The limiting value of friction force is given by μN, where μ is coefficient of kinetic friction (between the block and the horizontal surface) and N is normal reaction on block due to horizontal surface.