Embibe Experts Solutions for Chapter: Experiments in Physics, Exercise 1: Exercise-1

The diameter of a wire is measured with a screw gauze having least count $0.01 \mathrm{mm}$. Which of the following correctly expresses the diameter 

A student measured the diameter of a wire using a screw gauge with least count $0.001 \mathrm{cm}$ and listed the measurements. The correct measurement is:

What is vernier constant

The vernier of a circular scale is divided into $30$ divisions which coincide against $29$ divisions of main scale. Each main scale division is $0.5°$. The least count of the instrument is 

What is the reading of micrometer screwgauge shown in figure :-

A vernier callipers having $1$ main scale division $=0.1 \mathrm{cm}$ is designed to have a least count of $0.02 \mathrm{cm}$. If $n$ be the number of divisions on vernier scale and $m$ be the length of vernier scale, then

In a vernier calipers the main scale and the vernier scale are made up different materials. When the room temperature increases by $\mathrm{\Delta }T°\mathrm{C}$, it is found the reading of the instrument remains the same. Earlier it was observed that the front edge of the wooden rod placed for measurement crossed the $N^{\mathrm{th}}$ main scale division and $N+2 \mathrm{MSD}$  coincided with the $2^{\mathrm{nd}} \mathrm{VSD}$. Initially, $10 \mathrm{VSD}$  coincided with$9 \mathrm{MSD}$. If coefficient of linear expansion of the main scale is ${\alpha }_1$ and that of the vernier scale is ${\alpha }_2$ then what is the value of $\frac{{\alpha }_1}{{\alpha }_2}$ ? (Ignore the expansion of the rod on heating)

In the Searle's experiment, after every step of loading, why should we wait for two minutes before taking the readings? (More than one correct.)